swift - 无法使用 getDataInBackgroundWithBlock 将 PFFile 转换为 UIImage

Question

我有一个 updateCell 函数，我在 tableView 函数中调用它。

我正在尝试更新单元格并将 PFFile 转换为 UIImage，但我不断收到错误无法将类型“(NSData?, NSError?) -> Void”的值转换为预期参数类型“PFDataResultBlock” ？'

当我从 Parse 文档中得到这个时，我感到很困惑，而且我一生都无法找到解决方案或哪里出错了。这是我的 updateUI 函数。

func updateUI(venue: Venue) {
        venueLabel.text = venue.name
        let venueImageFile = venue.image

        venueImageFile.getDataInBackgroundWithBlock {
            (imageData: NSData?, error: NSError?) -> Void in
            if error == nil {
                if let imageData = imageData {
                    let image = UIImage(data:imageData)
                }
            }
        }
    }

这是 Venue 类

class Venue {

    private var _name: String!
    private var _location: String!
    private var _image: PFFile!

    var name: String {
        return _name
    }

    var location: String {
        return _location
    }

    var image: PFFile {
        return _image
    }

    init(name: String, location: String, image: PFFile) {
        self._name = name
        self._location = location
        self._image = image
    }
}

非常感谢任何帮助。现在我不知道该转向哪里。

Answer 1

基本上我找不到使用 getDataInBackgroundWithBlock 的解决方案，所以我最终安装了 Parse UI，它完美地解释了它......

PFImageView

Many apps need to display images stored in the Parse Cloud as PFFiles. However, to load remote images with the built-in UIImageView involves writing many lines of boilerplate code. PFImageView simplifies this task by abstracting away these parts.

一旦我将其导入到我的 swift 文件中，我所要做的就是:

@IBOutlet weak var venueImage: PFImageView! // Make sure it's this class in the storyboard. It's default would be UIImageView.

func updateUI(venue: Venue) {
    venueLabel.text = venue.name

    venueImage.file = venue.image
    venueImage.loadInBackground()
}

:)