ios - 创建XMPPRoom时如何设置和获取roomName(组名)？

Question

我正在尝试创建 XMPPRoom，但无法设置房间名称，并且收到的节格式不包含房间名称，请帮我解决后端可以看到房间名称的问题。

这是我创建 xmppRoom 的代码。

    func createGroupChat(){

   // membersToInvite = members

    let xmppRoomMemoryStorage = XMPPRoomMemoryStorage()

    let currentTimeMills = self.currentTimeMillis()
    let createdBy = (appDelegate.xmppStream?.myJID.user)! as String

    let jidString = String(format: "group%@_%@%@",currentTimeMills,createdBy,"@conference.hostname")

    let xmppJid = XMPPJID(string: jidString)
    let xmppRoom = XMPPRoom.init(roomStorage: xmppRoomMemoryStorage, jid: xmppJid)


    xmppRoom?.activate(appDelegate.xmppStream)
    xmppRoom?.addDelegate(self, delegateQueue: DispatchQueue.main)
    xmppRoom?.join(usingNickname: appDelegate.xmppStream?.myJID.full(), history: nil)

}

func xmppRoomDidCreate(_ sender: XMPPRoom!) {

    print(sender)

}


 func xmppRoomDidJoin(_ sender: XMPPRoom!) {

    sender.fetchConfigurationForm()

    for JID in selectedParticipantsAry {

        sender.editPrivileges([XMPPRoom.item(withAffiliation: "member", jid: XMPPJID(string: JID as! String))])

        sender.inviteUser(XMPPJID(string: JID as! String), withMessage: "THIS IS GROUP MESSAGE")

    }

}


func xmppRoom(_ sender: XMPPRoom!, didFetchConfigurationForm configForm: DDXMLElement!)
{

    let newConfig: DDXMLElement = configForm.copy() as! DDXMLElement
    let fields = newConfig.elements(forName: "field")

    for field in fields {
        let vars = field.attribute(forName: "var")
        // Make Room Persistent
        if (vars?.stringValue == "muc#roomconfig_persistentroom") {
            field.removeChild(at: 0)
            field.addChild(DDXMLElement(name: "value", stringValue : "1"))

        }else if (vars?.stringValue == "muc#roomconfig_roomname"){

            field.removeChild(at: 0)
            field.addChild(DDXMLElement(name: "value", stringValue : "GroupNameString"))
        }
    }

    sender.configureRoom(usingOptions: newConfig)

}

  func xmppStream(_ sender: XMPPStream!, didSend message: XMPPMessage!){

 <message to="group1480576001764.846924_XXX@conference.hostname"><x   xmlns="http://jabber.org/protocol/muc#user"><invite to="XXXXX@hostname">   <reason>THIS IS GROUP MESSAGE</reason></invite></x></message>  

 }

func xmppStream(_ sender: XMPPStream!, didReceive message: XMPPMessage!){

  <message xmlns="jabber:client"  from="group148057strong text6001764.846924_XXXX@conference.hostname" to="XXXX@hostname/33932018081480575881630558" type="groupchat" id="75252205"><x xmlns="http://jabber.org/protocol/muc#user"><status code="104"></status></x>   </message>
 }

Answer 1

在您的代码中，有两个不同的房间名称:

1. groupxxx 中

   字符串(格式:“group%@_%@%@”，currentTimeMills，createdBy，“@conference.hostname”)

格式为roomName@conference.hostname。

GroupNameString 在配置表单中设置。

你说的是哪一个？

对于 #1，它位于 from 节中，您只需将其从 jid 中取出即可。

对于#2，它不会包含在节中，您必须请求房间信息。 http://xmpp.org/extensions/xep-0045.html#disco-roominfo