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ios - UISearchController更新搜索结果问题

转载 作者:行者123 更新时间:2023-11-30 12:48:51 26 4
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我的问题是,当我尝试过滤它时,我已经在 Swift 3 中实现了 UISearchController 它是很容易过滤的简单数组,但我的情况有点不同,我有一个数组,我从 中获取所有数据>SQLite 数据库 在类中,因此它是类的数组

managerControlClassArray 包含类数组的所有内容。

我想过滤 updateSearchResults 委托(delegate)方法中的内容,但这确实很困难并且卡住了,我做了很多研究,在没有得到我想要的查询后,我发现 StackOverflow 非常有用,如果有人帮助的话,我会质疑它我,我将不胜感激。

一些代码逻辑:

manager = ModelManager.getInstance().getAllManager()
// I get all the objects using singleton

//manager class has following data
id, title, designation, salary

//In TableView i want to display data by using that

let managerVar = manager[indexPath.row]
cell.textLabel.text = managerVar.title

编辑:

MasterTableViewController.swift

import UIKit

class MasterTableViewController: UITableViewController, UISplitViewControllerDelegate, UISearchResultsUpdating {

var array: NSMutableArray! = NSMutableArray()

var managerArray = [foodManager]()

var filteredmanagerArray = [foodManager]()
var searchController = UISearchController(searchResultsController: nil)


override func viewDidLoad() {
super.viewDidLoad()

// Set the AppTitle using Config File
self.title = GL_Appname

managerArray = ModelManager.getInstance().getAllManagers()

filteredmanagerArray = managerArray

//copyTitleArrayForSearch()

self.tableView.reloadData()

self.splitViewController!.delegate = self;
self.splitViewController!.preferredDisplayMode = UISplitViewControllerDisplayMode.allVisible

//Seach Result Controller
self.searchController.searchResultsUpdater = self
self.searchController.dimsBackgroundDuringPresentation = false
self.searchController.definesPresentationContext = true
self.searchController.searchBar.sizeToFit()
self.tableView.tableHeaderView = self.searchController.searchBar


}



/* func copyTitleArrayForSearch(){

for i in 0..<managerArray.count{
let fd = managerArray[i]

//titleArray.append(fd.title)
}

} */

override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}

// MARK: - Table view data source

override func numberOfSections(in tableView: UITableView) -> Int {
return 1
}

override func tableView(_ tableView: UITableView, heightForRowAt indexPath: IndexPath) -> CGFloat{
return 60
}

override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

if searchController.isActive{
return filteredmanagerArray.count
}
else{
return managerArray.count
}
}

override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath)

cell.textLabel?.adjustsFontSizeToFitWidth = true
cell.textLabel?.lineBreakMode = NSLineBreakMode.byWordWrapping
cell.textLabel?.numberOfLines = 3

cell.textLabel?.textColor = UIColor.black
cell.textLabel?.font = UIFont(name: "ChalkboardSE-Light", size: 14.0)

if searchController.isActive {
let fra = filteredmanagerArray[indexPath.row]
cell.textLabel?.text = fra.title.uppercased()
}
else{
let fd = managerArray[indexPath.row]
cell.textLabel?.text = fd.title.uppercased()
}

return cell
}

func updateSearchResults(for searchController: UISearchController) {
self.tableView.reloadData()

self.filteredRecipeArray.removeAll(keepingCapacity: false)
let searchPredicate = NSPredicate(format: "SELF CONTAINS[c] %@", searchController.searchBar.text!)

let array = (self.filteredRecipeArray as NSArray).filtered(using: searchPredicate)

self.filteredRecipeArray = array as! [foodRecipe]

self.tableView.reloadData()
}


override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {

print("DidSelect index Path: \(indexPath.row)")
//print("Filtered Manager Index: \(filteredmanagerArray[indexPath.row]))")

self.performSegue(withIdentifier: "showDetail", sender: self)

}

// MARK: - Navigation

// In a storyboard-based application, you will often want to do a little preparation before navigation
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

if segue.identifier == "showDetail" {

let index = self.tableView.indexPathForSelectedRow! as IndexPath

let nav = segue.destination as! UINavigationController

let vc = nav.viewControllers[0] as! DetailViewController

if searchController.isActive {

print("Manager Array Index: \(managerArray[index.row])")

//var currentFilteredIndex = filteredmanagerArray[(indexPath as NSIndexPath).row]
print("Filtered Manager Array Index: \(filteredmanagerArray[index.row])"
}
else{
vc.selectedmanagerArray = [managerArray[index.row]]

}

//vc.titleText = self.array.object(at: (index as NSIndexPath).row) as! String
self.tableView.deselectRow(at: index, animated: true)

}

}

// MARK: - UISplitViewControllerDelegate

func splitViewController(_ splitViewController: UISplitViewController, collapseSecondary secondaryViewController: UIViewController, onto primaryViewController: UIViewController) -> Bool {

return true

}
}

Manager.swift

class Manager: NSObject{

var id: String = String()
var title: String = String()
var ManagerDesignation: String = String()

}

谢谢。

再见。

最佳答案

我们可以只使用 Swift 内置的 filter 方法吗?

func updateSearchResults(for searchController: UISearchController) {
self.tableView.reloadData()

self.filteredRecipeArray.removeAll(keepingCapacity: false)
guard let searchText = searchController.searchBar.text else {
return
}

let array = managerArray.filter {
return $0.id.range(of: searchText) != nil ||
$0.title .range(of: searchText) != nil ||
$0.ManagerDesignation.range(of: searchText) != nil
}

self.filteredRecipeArray = array

self.tableView.reloadData()
}

编辑

更新了最新 Swift 3 语法的答案

关于ios - UISearchController更新搜索结果问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41270362/

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