JavaScript 确认框返回代码而不是函数值

Question

我创建了一个真正简单的表单并使用 JS 访问单选按钮的值，然后进行快速计算并基于函数在弹出框中返回一个字符串。问题是当单击按钮时，弹出窗口返回被调用函数的代码而不是字符串。

     <div id="questionaire">
        <div id="question1">    
            <h2>How familiar are you with Javascript?</h2><br>
            <form id="first_q">
                <input type="radio" name="q1" value="4">Very Experienced.</input><br>
                <input type="radio" name="q1" value="3">I've Worked with the Basics.</input><br>
                <input type="radio" name="q1" value="2">I Only Know Its a Programming Language.</input><br>
                <input type="radio" name="q1" value="1">Java...Mmm, Coffee sounds GOOD!</input>
            </form>
        </div>
        <div id="question2">
            <h2>How much do you like to code?</h2><br>
            <form id="second_q">
                <input type="radio" name="q2" value="4">I think about coding during sex!</input><br>
                <input type="radio" name="q2" value="3">It's safe to say, I take coding pretty_seriously.</input><br>
                <input type="radio" name="q2" value="2">I would consider it my cold-weather hobby.</input><br>
                <input type="radio" name="q2" value="1">Technology is cool.</input>
            </form>
        </div>
    </div>
    <div id="answer">
        <button id="color-switcher">TELL ME MORE...</button>
    </div>

外链JS

var q1_rating = function() {
var first_q_answer = document.getElementsByName("q1");

for(var i = 0; i < first_q_answer.length; i++) {
  if(first_q_answer[i].checked == true) {
    q1_value = first_q_answer[i].value;
  }
}

return parseFloat(q1_value);
};

var q2_rating = function() {
var second_q_answer = document.getElementsByName("q2");

for(var i = 0; i < second_q_answer.length; i++) {
  if(second_q_answer[i].checked == true) {
    q2_value = second_q_answer[i].value;
  }
}

return parseFloat(q2_value);
};

var final_rating = function() {
total_value = (q1_rating + q2_rating);

if (total_value > 6) {
    return "You're a TRUE NERD ready to conquer the world.";
} else if (total_value > 4 && total_value <=6) {
    return "You need some more work, but you're coming along nicely.";
} else if (total_value >2 && total_value <=4) {
    return "You need to step up your nerd game pronto!";
} else {
    return "You're more jock than nerd";
}
};

document.getElementById('color-switcher').addEventListener('click', function(){
    confirm(final_rating);
})

Answer 1

你需要调用final_rating函数

 confirm(final_rating());

目前，您正在传递函数的引用