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ios - 在 Swift 中将图像从 tableView 传递到 viewController

转载 作者:行者123 更新时间:2023-11-30 12:48:17 25 4
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我在 Assets 文件夹中有图像,我试图将数据从 tableView 传递到下一个 viewController。我有两个表,我创建了 UIImageView 的导出。
ThirdView.swift 包含结构
导入 UIKit

struct ThirdView {
var ThirdViewArray = [String]()
var Pic = [String]()
}

SecondTableViewController.swift 包含

class SecondTableViewController: UITableViewController {

var ExerciseListArray = [String]()
var SecondAnswerArray = [String]()



override func viewDidLoad() {
super.viewDidLoad()
}
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return ExerciseListArray.count
}
override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
var Cell = self.tableView.dequeueReusableCell(withIdentifier: "SecondCell", for: indexPath) as UITableViewCell
Cell.textLabel?.text = ExerciseListArray[indexPath.row]

return Cell
}

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
var indexPath: NSIndexPath = self.tableView.indexPathForSelectedRow! as NSIndexPath
var DestViewController = segue.destination as! ExercisesViewController
DestViewController.FirstString = SecondAnswerArray[indexPath.row]
DestViewController.ExerciseImage = SecondAnswerArray[indexPath.row]
}


}

但是,SecondAnswerArray 是一种 String 类型,我收到错误:
“无法将 type String 的值分配给 UIImage 类型”行 DestViewController.ExerciseImage = SecondAnswerArray[indexPath.row]
最后,FirstTableViewController.swift: FirstTableViewController 类:UITableViewController {

var BodyPartsArray = [String]()
var SecondArray = [SecondTable]()
var ThirdArray = [ThirdView]()

override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
BodyPartsArray = ["Neck", "Shoulders", "Upper Arms", "Forearms", "Back", "Chest", "Waist", "Hips", "Thighs", "Calves"]

SecondArray = [
SecondTable(SecondTitle: ["Neck1","Neck2","Neck3"]),
SecondTable(SecondTitle: ["Shoulders1","Shoulders2","Shoulders3"]),
SecondTable(SecondTitle: ["Upper Arms1","Upper Arms2","Upper Arms3"]),
SecondTable(SecondTitle: ["Forearms1","Forearms2","Forearms3"]),
SecondTable(SecondTitle: ["Back1","Back2","Back3"]),
SecondTable(SecondTitle: ["Chest1","Chest2","Chest3"]),
SecondTable(SecondTitle: ["Waist1","Waist2","Waist3"]),
SecondTable(SecondTitle: ["Hips1","Hips2","Hips3"]),
SecondTable(SecondTitle: ["Thighs1","Thighs2","Thighs3"]),
SecondTable(SecondTitle: ["Calves1","Calves2","Calves3"])]

ThirdArray = [
ThirdView(ThirdViewArray: ["NeckText1","NeckText2","NeckText3"], Pic: []),
ThirdView(ThirdViewArray: ["ShouldersText1","ShouldersText2","ShouldersText3"], Pic: ["310","311","312"]),
ThirdView(ThirdViewArray: ["Upper ArmsText1","Upper ArmsText2","Upper ArmsText3"], Pic: ["313","314","315"]),
ThirdView(ThirdViewArray: ["ForearmsText1","ForearmsText2","ForearmsText3"], Pic: ["","",""]),
ThirdView(ThirdViewArray: ["BackText1","BackText2","BackText3"], Pic: ["","",""]),
ThirdView(ThirdViewArray: ["ChestText1","ChestText2","ChestText3"], Pic: ["","",""]),
ThirdView(ThirdViewArray: ["WaistText1","WaistText2","WaistText3"], Pic: ["","",""]),
ThirdView(ThirdViewArray: ["HipsText1","HipsText2","HipsText3"], Pic: ["","",""]),
ThirdView(ThirdViewArray: ["ThighsText1","ThighsText2","ThighsText3"], Pic: ["","",""]),
ThirdView(ThirdViewArray: ["CalvesText1","CalvesText2","CalvesText3"], Pic: ["","",""])]
}

override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return BodyPartsArray.count
}

override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let Cell = self.tableView.dequeueReusableCell(withIdentifier: "Cell", for: indexPath) as UITableViewCell
Cell.textLabel?.text = BodyPartsArray[indexPath.row]

return Cell
}

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

let indexPath: NSIndexPath = self.tableView.indexPathForSelectedRow! as NSIndexPath
let DestViewController = segue.destination as! SecondTableViewController
var SecondTableArrayTwo: SecondTable
SecondTableArrayTwo = SecondArray[indexPath.row]
DestViewController.ExerciseListArray = SecondTableArrayTwo.SecondTitle


var ThirdAnswerArray: ThirdView
ThirdAnswerArray = ThirdArray[indexPath.row]
DestViewController.SecondAnswerArray = ThirdAnswerArray.ThirdViewArray
DestViewController.SecondAnswerArray = ThirdAnswerArray.Pic
}

}

再次,我在 DestViewController.SecondAnswerArray = ThirdAnswerArray.Pic 行上遇到了相同的错误

练习 View Controller :
导入 UIKit

类ExercisesViewController:UIViewController {

@IBOutlet weak var TextView: UITextView!
@IBOutlet weak var ImageView: UIImageView!

var FirstString = String()
var ExerciseImage = String()

override func viewDidLoad() {

TextView.text = FirstString
ImageView.image = ExerciseImage

}
}

任何人都可以帮助我解决这个错误,并向我展示将图片从资源加载到 FirstTableViewController.swift ThirdArray 中的 UIImageView 的正确方法吗?
谢谢

最佳答案

如果您可以分享ExercisesViewController的代码以获得更好的建议,那就太好了,但这可能对您有帮助:

首先,ExercisesViewController 中的变量 DestViewController.ExerciseImage 可能是 UIImage 类型,在您的数组 SecondAnswerArray 上,您包含 String 类型的对象。如此处声明:

var SecondAnswerArray = [String]()

当您将 SecondAnswerArray 中的值分配给预期为 UIImage 的对象时,您会收到错误消息

Cannot assign value of type String to type UIImage"

将ExercisesViewController.ExerciseImage的类型更改为String类型,这将解决您的第一个问题。

要从资源文件夹中设置图像,您只需将图像文件名分配给UIImage,例如:

let img = UIImage(named: "NAME_OF_YOUR_FILE_WITHOUT_EXTENSION")

然后将该图像设置为 UIImageView

imageView.image = img

希望有帮助

关于ios - 在 Swift 中将图像从 tableView 传递到 viewController,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41335294/

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