javascript - 如何通过AJAX传递表单值和个体值？

Question

如何将表单值和用户 ID 传递给 ajax？

JavaScript:

jQuery("#DoneBtn").click(function(){
    var data = $("#insertsubs_form").serialize();
    <?php 
        $db = JFactory::getDBO();
        $user = JFactory::getUser();
    ?>
    var userid = <?php echo $user->id; ?>
    $.ajax({
        data: {
            data:data,
            userid : userid
        },
        type: "post",
        url: "../insert_subs.php",
        success: function(data){
                alert(data);
        }
    });
});

在 insert_subs.php 中:

$userid = $_GET['userid'];

**** 感谢 Deena 的 Anand Patel。两者都是我想要的相同答案! :D 还要感谢 epascarello!我没有尝试过，但我认为它也能正常工作。 :)

Answer 1

试试这个

        jQuery("#DoneBtn").click(function(){

            <?php 
                $db = JFactory::getDBO();
                $user = JFactory::getUser();
            ?>
            var userid = <?php echo $user->id; ?>;

            var data = $("#insertsubs_form").serialize() + "&userid=" + userid;


            $.ajax({
                data: data,
                type: "post",
                url: "../insert_subs.php",
                success: function(data){
                    alert(data);
                }
            });
        })