ios - 想要将 API 数据显示到标签(Swift、Alamofire)

Question

我正在使用 Alamofire 调用 Riot API，我想显示它调用的信息。我的 get 请求正在运行，我只是不知道如何链接到应用程序中的标签。我已经包含了代码的屏幕截图!

• Code

• Response

这只是我正在创建的一个简单的应用程序!

func callAlamo(url: String){
    Alamofire.request(url).responseJSON(completionHandler: {
    response in
    self.pasrseData(JSONData: response.data!)
    })
  }

func parseData(JSONData: Data){
  do {
        var readableJSON = try JSONSerialization.jsonObject(with: JSONData, options: .mutableContainers) as? JSONStandard
        print(readableJSON)
}

catch {
    print(error)
  }
}

Answer 1

不需要序列化，因为 Alamofire 的 responseJSON 已经完成了。由于我不知道 JSON 对象内部有什么，所以假设您返回了年龄和姓名:

struct InfoModel { // this struct will decompose our JSON object from the response that we get 
    var age:Int
    var name:String
    init(json:Dictionary<String,Any>?) { 
        guard let dict = json,
        let age = dict["age"] as? Int,
        let name = dict["name"] as? String
            else {fatalError() }
        self.age = age
        self.name = name

    }
}

func parse(url: String, completion:@escaping (InfoModel)-> Void) {
    Alamofire.request(url).responseJSON {response in
        // get the JSON dictionary
        if let JSON = response.result.value {
            // no need to decompose your object since your struct does it inside of its initializer
            completion(InfoModel(json: JSON as? Dictionary<String, Any>))
        }
    }
}
// call this function anywhere
parse(url: "") { (m:InfoModel) in
   print("age= \(m.age), name= \(m.name)")
   // now populate your label 
   labelOne.text = "\(m.age)"
   labelTwo.text = name
}