swift - swift 3 中计算属性和带有闭包的属性集之间的区别？

Question

这个问题已经有答案了:

What does this mean? Variable declared followed by a block without assignment (3 个回答)

Getter vs Computed property. What would warrant using one of these approaches over the other? (2 个回答)

已关闭 6 年前。

我已经阅读了这个( Difference between computed property and property set with closure )有用的问题，但它没有完全回答我想知道的问题。

它回答了以下之间的区别:

//closure
var pushBehavior: UIPushBehavior = {
    let lazilyCreatedPush = UIPushBehavior()
    lazilyCreatedPush.setAngle(50, magnitude: 50)
    return lazilyCreatedPush
}()

和

//computed
var pushBehavior: UIPushBehavior {
    get{
        let lazilyCreatedPush = UIPushBehavior()
        lazilyCreatedPush.setAngle(50, magnitude: 50)
        return lazilyCreatedPush
    }
}

我明白这一点。现在，如果我们更改第一个，第二个示例中的计算变量与此之间有什么区别:

var pushBehavior: UIPushBehavior {
    let lazilyCreatedPush = UIPushBehavior()
    lazilyCreatedPush.setAngle(50, magnitude: 50)
    return lazilyCreatedPush
}

对我来说，这与 get{} 完全相同，但没有 get 关键字。是这样吗？如果是这样，为什么我们有 get 关键字？

Answer 1

没有区别。

来自documentation

You can simplify the declaration of a read-only computed property by removing the get keyword and its braces.