ios - 数组打印 API 调用的相同结果

Question

我正在构建一个应用程序，您可以在其中输入成分，然后根据您的输入返回一堆食谱。我正在使用 alamofire 调用 API，这些似乎很成功。我遇到的问题是我的测试调用中的 6 个结果重复 1 个配方 6 次，而不是在单独的单元格中返回所有结果。这是API调用代码:

import Alamofire

class RecipeAp: NSObject{

var concoctions = [RecipeDetails]()

func provideRecipeDetailsForName(name: String, completed:@escaping ([RecipeDetails]) -> Void) {
    let urlSearchString = URL_FULL + "onion" + "soup"
    Alamofire.request(urlSearchString).responseJSON(completionHandler: { response in
        let details = RecipeDetails()
        let result = response.result
        if let dict = result.value as? Dictionary<String, AnyObject> {

            if let matches = dict["matches"] as? [[String: Any]] {
                for ingredient in matches {
                    if let name = ingredient["ingredients"] as? [String] {
                        details.ingredients = name
                        self.concoctions.append(details)

                    }
                }

                for recipeName in matches {
                    if let name = recipeName["recipeName"] as? String {
                        details.recipeTitle = name
                        print("the recipe name = \(name.debugDescription)")
                        self.concoctions.append(details)

                    }

                }

            }

            completed(self.concoctions)

        }



    })

}

}

这是我的模型:

  class RecipeDetails: NSObject {
   var recipeID: String?
   var recipeImageURL: String?
   var recipeTitle: String?
   var recipeSourceURL: String?
   var recipePublisher: String?
   var ingredients: [String]?
}

这是我的自定义单元格设置

   import UIKit

 class RecipeListCustomCell: UITableViewCell {


@IBOutlet weak var recipeTitle: UILabel!
@IBOutlet weak var recipeUrl: UILabel!

var recipe: RecipeDetails? {

    didSet {

        updateView()

    }

}

func updateView() {

    recipeTitle.text = recipe?.recipeTitle
    recipeUrl.text = recipe?.recipeSourceURL


   }

 }

最后这是我的 viewController

 import UIKit

 class MainVC: UIViewController {

@IBOutlet weak var tableView: UITableView!

var recipe = RecipeAp()
var results = [RecipeDetails]()

override func viewDidLoad() {
    super.viewDidLoad()

    loadRecipes()

}


     func loadRecipes() {

    recipe.provideRecipeDetailsForName(name: "onion" + "soup") { (response) in

        self.results = response
        self.tableView.reloadData()

    }

   }

 }

 extension MainVC: UITableViewDataSource {

 func tableView(_ tableView: UITableView, numberOfRowsInSection 
 section: Int) -> Int {
    return results.count
}

  func tableView(_ tableView: UITableView, cellForRowAt indexPath: 
  IndexPath) -> UITableViewCell {

    let cell = tableView.dequeueReusableCell(withIdentifier: 
    "RecipeListCustomCell", for: indexPath) as! RecipeListCustomCell
    let recipe = results[indexPath.row]
    cell.recipe = recipe

    return cell


   }

 }

不确定如何在每个单元格中单独显示所有食谱。我还附上了一些关于我从 API 中返回的内容和模拟器中显示的屏幕截图。

Answer 1

您仅为每个响应创建一个 RecipeDetails 实例。因此，您重复地将完全相同的引用添加到您的 self.concoctions 中。

您可能需要编写如下内容:

func provideRecipeDetailsForName(name: String, completed: @escaping ([RecipeDetails]) -> Void) {
    let urlSearchString = URL_FULL + "onion" + "soup"
    Alamofire.request(urlSearchString).responseJSON(completionHandler: { response in
        let result = response.result
        if let dict = result.value as? Dictionary<String, AnyObject> {

            if let matches = dict["matches"] as? [[String: Any]] {
                for match in matches {
                    //### Create a new instance for each iteration.
                    let details = RecipeDetails()
                    if let ingredients = match["ingredients"] as? [String] {
                        details.ingredients = ingredients
                    }
                    if let recipeName = match["recipeName"] as? String {
                        details.recipeTitle = recipeName
                        print("the recipe name = \(recipeName.debugDescription)")
                    }
                    //### Add the instance once in the iteration
                    self.concoctions.append(details)
                }
            }

            completed(self.concoctions)
        }
    })
}