javascript - 删除重复项并在 y :axis 中只计算一个

Question

如何去掉Duplicate 从而显示一个只有count为1s的唯一标签。

我的值(value)观在哪里

喜欢

[
  {"y":2,"label":"Adnim"},
  {"y":2,"label":"Adnim"},
  {"y":0,"label":"Adnim"},
  {"y":0,"label":"Adnim"},
  {"y":2,"label":"Adnim2"},
  {"y":2,"label":"Adnim2"},
  {"y":2,"label":"Adnim2"},
  {"y":0,"label":"Adnim2"},
]

我需要的最终输出是

 [
  { y: 2 ,  label: 'Adnim' },
 {y: 3 ,  label: 'Adnim2'},
] 

忽略“0”只算“1”并唯一显示

仅供引用:标签值将发生变化

Answer 1

希望我没听错。该程序查找每个 label 的出现次数并将其放入相应的 y 字段。

var list = [
  {"y":2,"label":"Adnim"},
  {"y":2,"label":"Adnim"},
  {"y":0,"label":"Adnim"},
  {"y":0,"label":"Adnim"},
  {"y":2,"label":"Adnim2"},
  {"y":2,"label":"Adnim2"},
  {"y":2,"label":"Adnim2"},
  {"y":0,"label":"Adnim2"},
]

var counters = {}
var result = [];
var label;

list.forEach(function(el){
    label = el.label;
    // Skip zero y's
    if (el.y === 0) return;

    // Increase counter values
    if (counters.hasOwnProperty(label)) {
        counters[label] += 1;
    } else {
        counters[label] = 1;
    }
});

// Convert counters object to array of objects
for (var label in counters) {
    result.push({'label': label, 'y': counters[label]});
}

结果是:

[{"label":"Adnim","y":2},{"label":"Adnim2","y":3}]