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ios - SpriteKit 中的分享按钮崩溃了?

转载 作者:行者123 更新时间:2023-11-30 12:20:34 25 4
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所以我有一个共享按钮,它可以打开 UI-Activity。当我单击共享按钮时,它崩溃并收到以下错误:libc++abi.dylib:因未捕获的 NSException 类型异常而终止。任何人都可以检查我的代码并看看发生了什么事吗?谢谢*最后一件事:当他们返回游戏时,共享按钮保留在屏幕上。我怎样才能隐藏它,比如只在游戏结束场景中显示它?

here is my code

    shareButton = UIButton(frame: CGRect(x: 0, y:0, width: view.frame.size.width / 3, height: 60))

// shareButton.center = CGPoint(x: self.size.width/4, y: self.size.height/4)
shareButton.center = CGPoint(x: view.frame.size.width / 2 - 70, y: view.frame.size.height / 1.275)
shareButton.center = CGPoint(x: self.frame.midX, y: 3*self.frame.height/4)

shareButton.setTitle("Share", for: UIControlState.normal)
shareButton.setTitleColor(UIColor.white, for: UIControlState.normal)
shareButton.addTarget(self, action: (#selector(GameOver.pressed(_:))), for: .touchUpInside)


// shareButton.removeFromSuperview()
self.view?.addSubview(shareButton)



func pressed(_ sender: UIButton!) {


let va = self.view?.window?.rootViewController

let myText = "Can you beat my score \(score) in the game of Balls"

let activityVC:UIActivityViewController = UIActivityViewController(activityItems: [myText], applicationActivities: nil)

va?.present(activityVC, animated: true, completion: nil)




}

最佳答案

如果函数 pressed: 位于 GameOver 类中,请勿将目标添加为 self。而是将目标添加为 GameOver

的对象
let objGameOver = // Get your existing GameOver class instance here
shareButton.addTarget(objGameOver, action: (#selector(GameOver.pressed(_:))), for: .touchUpInside)

关于ios - SpriteKit 中的分享按钮崩溃了?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44841549/

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