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swift - 如何从通知中访问 userInfo 属性?

转载 作者:行者123 更新时间:2023-11-30 12:17:34 27 4
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我调用NotificationCenter的post方法时有一个方法:

func processMessage(message: CocoaMQTTMessage) {
Log.d("DestinationTopicHandler: handling message")
//message.string: Contains the response of the server
print(message.string!) // print the response (String)

bus.post(name: .DestinationRespReceived, userInfo: [message.string! : String()])
}

这是我的 message.string 打印:

{     "req_token":"test",   "conv_token":"test",   "ts":"2017-04-05 12:00:00.123",   "code":0,   "message":"ACCESO CONCEDIDO",   "auth_token":"test",   "response":{        "type":"test",      "data":{           "destinos":[              {                 "idDestino":"1",               "desDestino":"ASUNCION"            },            {                 "idDestino":"2",               "desDestino":"MIAMI"            }         ]      }   }}

This is my post method declaration:

func post(name: Notification.Name, userInfo info : [AnyHashable : Any]? = nil) {
NotificationCenter.default
.post(name: name, object: nil, userInfo: info)
}

到目前为止一切正常。这是我尝试访问 userInfo 数据的 final方法:

public func responseReceived(_ notification: Notification) {
if processed {
return
}

processed = true
responseReceived = true
Log.i("responseReceived:")

guard let userInfo = notification.userInfo, let msg = userInfo["idDestino"] as? String else {
Log.v("No userInfo found in notification")
callback.onResponseReceived(nil)

return
}

if let json = msg.json {
callback.onResponseReceived(Response_Base(json: json.dictionary))
} else {
Log.v("Could not parse msg")
callback.onResponseReceived(nil)
}
}

问题是我不知道为什么程序总是返回“在通知中找不到 userInfo”。有人可以帮我吗?

我的用户信息输出是:

[AnyHashable("{ \n \"req_token\":\"test\",\n \"conv_token\":\"test\",\n \"ts\":\"2017-04-05 12:00:00.123\",\n \"code\":0,\n \"message\":\"ACCESO CONCEDIDO\",\n \"auth_token\":\"jakldsfjalkdfj\",\n \"response\":{ \n \"type\":\"test\",\n \"data\":{ \n \"destinos\":[ \n { \n \"idDestino\":\"1\",\n \"desDestino\":\"ASUNCION\"\n },\n { \n \"idDestino\":\"2\",\n \"desDestino\":\"MIAMI\"\n }\n ]\n }\n }\n}"): ""]

最佳答案

好的...我解决了我的问题...感谢@martin R

问题出在这一行:

 bus.post(name: .DestinationRespReceived, userInfo: [message.string! : String()])

我没有意识到键是我的 userInfo 的第一个元素,第二个元素是值。所以我像这样更正了 userInfo 位置的元素:

bus.post(name: .DestinationRespReceived, userInfo: ["msg" : message.string!])

所以...在我的函数中 responseReceived 现在是正确的:

 guard let userInfo = notification.userInfo, let msg = userInfo["msg"] as? String else {

Log.v("No userInfo found in notification")
callback.onResponseReceived(nil)

return
}

谢谢!

关于swift - 如何从通知中访问 userInfo 属性?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45198956/

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