ios - 如何让按钮移动到另一个ViewController

Question

如何使 Button 移动到另一个 ViewController ？

任何人都可以帮助我吗，这是我的代码。我尝试使用 button1: UIButton! 但出现错误

class Interest1
{
    var title = ""
    var description = ""
    var featuredImage: UIImage!
    var button1: UIButton!
    var button2: UIButton!
    var button3: UIButton!
    var button4: UIButton!

    init(title: String, featuredImage: UIImage!, button1: UIButton!)
    {
        self.title = title
        self.featuredImage = featuredImage
    }

    static func createInterest() -> [Interest1]
    {
        return [
           Interest1(title: "One", featuredImage: UIImage(named:"001.png")!, button1: UIButton), // I got error Here i don't know why
            Interest1(title: "Two", featuredImage: UIImage(named:"002.png")!),
            Interest1(title: "Three", featuredImage: UIImage(named:"003.png")!),
            Interest1(title: "Four", featuredImage: UIImage(named:"004.png")!),
        ]    
    }
}

代码:

func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int
{
    return interests3.count //error
}

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell
{
    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "1", for: indexPath as IndexPath) as! interestCollectionViewCell
    cell.interest2 = self.interests3[indexPath.item] //error
    return cell
}

错误是使用了无法解析的标识符“interests3”

Answer 1

我发现您的代码有几个问题。修复它们会很好。

您不必将参数命名为“button1” - “button”在这里更合适，因此您的构造函数可以像这样

init(title: String, featuredImage: UIImage!, button: UIButton!)

在这里强制展开并不是一个好的方法。最好将其删除，因此构造函数为:

init(title: String, featuredImage: UIImage, button: UIButton)

现在，在构造函数内部您根本不使用按钮。我想你想设置它，比如

init(title: String, featuredImage: UIImage, button: UIButton)
    {
        self.title = title
        self.featuredImage = featuredImage
        self.button = button
    }

最后，在您创建的对象中，您使用的不是现有的构造函数:

Interest1(title: "Two", featuredImage: UIImage(named:"002.png")!)

您还必须提供按钮。所以，您可能想做这样的事情:

   static func createInterest() -> [Interest1]
        {
            return [
               Interest1(title: "One", featuredImage: UIImage(named:"001.png")!, button: someFirstButton), // I got error Here i don't know why
                Interest1(title: "Two", featuredImage: UIImage(named:"002.png")!, button: someSecondButton),
                Interest1(title: "Three", featuredImage: UIImage(named:"003.png")!, button: someThirdButton)
            ]    
        }

请注意，您可能想在内部提供按钮，而不是 someFirstButton、someSecondButton、someThirdButton

祝你好运