ios - 无法在 swift 3 中发布请求参数？

Question

这里我使用这个 Json 函数从 api 获取数据，但是在 let task = URLSession.shared.dataTask(with: request) { data, response, error in 这行之后，它移到了最后大括号并且不执行中间的剩余行，输出将是带有字典的数组，任何人都可以帮助我如何获得对此的响应？

func shippingmethodURL(shippingMethodAPI:String) {
        let url = NSURL(string: shippingMethodAPI)
        var request = URLRequest(url: url! as URL)
        request.httpMethod = "POST"
        print(shippingMethodAPI)
        let storyboard = UIStoryboard(name: "Main", bundle: nil)
        let addtoCartVC = storyboard.instantiateViewController(withIdentifier: "checkout") as! CheckoutViewController
        let parameters : [String: Any] = ["address":
            [ "region": "California",
                "region_code": "CA",
                "region_id": "12",
                "country_id": "US",
                "company": "Test",
                "telephone": "9492162752",
                "postcode": "43",
                "city": "Chennai",
                "firstname": "gdfgdgdfg",
                "lastname": "dgdfgdfgg",
                "email": "sfdsfsdf@gmail.com",
                "prefix": "",
                "sameAsBilling": 1,
                "street": ["Dsfdsfsd dfdsfdsf dsfsfdsfsf sdfsfdsfsdfC"]]]
        print(parameters)
        do {
            request.httpBody = try JSONSerialization.data(withJSONObject: parameters, options: .prettyPrinted)

        } catch let error {
            print(error.localizedDescription)
        }
        request.addValue("application/json", forHTTPHeaderField: "Content-Type")
        print(request)
        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let data = data, error == nil else {
                print("error=\(String(describing: error))")
                return
            }

            if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {
                print("statusCode should be 200, but is \(httpStatus.statusCode)")
                print("response = \(String(describing: response))")
            }
            let responseString = String(data: data, encoding: .utf8)
            print("responseString = \(responseString!)")
            let status = (response as! HTTPURLResponse).statusCode
            self.keyStatusCode = status
            print(status)
        }
    }

Answer 1

当您使用 dataTask 方法时，您将返回一个任务对象。所以你需要对其调用resume()。

创建任务后，必须通过调用其 resume() 方法来启动它。该任务调用 session 委托(delegate)上的方法来为您提供响应元数据、响应数据等。

Learn about :