javascript - 重构查找函数

Question

我正在尝试重构此功能，但碰壁了。该函数试图完成的是查找 JSON 对象中是否存在联系人，如果存在，则确定提供的第二个参数是否是指定对象上存在的属性。

var contacts = [
    {
        "firstName": "Akira",
        "lastName": "Laine",
        "number": "0543236543",
        "likes": ["Pizza", "Coding", "Brownie Points"]
    },
    {
        "firstName": "Harry",
        "lastName": "Potter",
        "number": "0994372684",
        "likes": ["Hogwarts", "Magic", "Hagrid"]
    },
    {
        "firstName": "Sherlock",
        "lastName": "Holmes",
        "number": "0487345643",
        "likes": ["Intriguing Cases", "Violin"]
    },
    {
        "firstName": "Kristian",
        "lastName": "Vos",
        "number": "unknown",
        "likes": ["Javascript", "Gaming", "Foxes"]
    }
];


function lookUpProfile(firstName, prop){
// Only change code below this line
for (var i = 0; i < contacts.length; i++) {
   if (contacts[i].firstName === firstName && contacts[i].hasOwnProperty(prop)) {
      return contacts[i][prop];
   }

}

  for (var j = 0; j < contacts.length; j++) {
   if (contacts[j].firstName !== firstName) {
      return "No such contact";
   } else if (!contacts[j].hasOwnProperty(!prop)) {
      return "No such property" ; 
   }

}

// Only change code above this line
}

// Change these values to test your function
lookUpProfile("kyle", "lastName");

Answer 1

过滤任何匹配项，如果找到该属性，则返回 true else false

function lookUpProfile(firstName, prop) {
  var list = contacts.filter(function (el) {
    return el.firstName === firstName;
  });
  return list.length && list[0][prop] ? true : false;
}

lookUpProfile("kyle", "lastName"); // false
lookUpProfile("Akira", "lastName"); // true
lookUpProfile("Akira", "password"); // false

DEMO