gpt4 book ai didi

javascript - 使用正则表达式从字符串中提取图像 url

转载 作者:行者123 更新时间:2023-11-30 11:56:34 27 4
gpt4 key购买 nike

我有一个看起来像这样的字符串:

var complicatedString = "<![CDATA[<img src=\"http://l.yimg.com/a/i/us/we/52/32.gif\"/>\n<BR />\n<b>Current Conditions:</b>\n<BR />Sunny\n<BR />\n<BR />\n<b>Forecast:</b>\n<BR /> Fri - Sunny. High: 23Low: 13\n<BR /> Sat - Thunderstorms. High: 25Low: 15\n<BR /> Sun - Thunderstorms. High: 28Low: 21\n<BR /> Mon - Partly Cloudy. High: 24Low: 17\n<BR /> Tue - Partly Cloudy. High: 26Low: 18\n<BR />\n<BR />\n<a href=\"http://us.rd.yahoo.com/dailynews/rss/weather/Country__Country/*https://weather.yahoo.com/country/state/city-23511893/\">Full Forecast at Yahoo! Weather</a>\n<BR />\n<BR />\n(provided by <a href=\"http://www.weather.com\" >The Weather Channel</a>)\n<BR />\n]]>"

我需要提取 http://l.yimg.com/a/i/us/we/52/32.gif 。我想出的正则表达式是:

var re = /(alt|title|src)=(\\"[^"]*\")/i;

参见 fiddle :https://jsfiddle.net/47rveu62/2/

我不确定为什么,但这行不通。

var re = /(alt|title|src)=(\\"[^"]*\")/i;
var m;
do {
m = re.exec(complicatedString);
} while(m !== null);

更新:Regex 101 声称它有效 https://regex101.com/r/oV2hO2/1

最佳答案

问题出在正则表达式上。

字符串中的反斜杠用于转义双引号字符串中的双引号。 反斜杠是转义字符而不是字符串的一部分。因此,在正则表达式中不需要这些字符。

Here's how the string looks when logged in console

var re = /(alt|title|src)=(\\"[^"]*\")/i;
^^ ^ // Remove those

使用

/(alt|title|src)=("[^"]*")/gi;

此处的g 标志是必需的,因为正则表达式的lastIndex 属性未被RegExp#exec 更新。下一次迭代,正则表达式将从相同的索引开始搜索,从而进入无限循环。 MDN

var complicatedString = "<![CDATA[<img src=\"http://l.yimg.com/a/i/us/we/52/32.gif\"/>\n<BR />\n<b>Current Conditions:</b>\n<BR />Sunny\n<BR />\n<BR />\n<b>Forecast:</b>\n<BR /> Fri - Sunny. High: 23Low: 13\n<BR /> Sat - Thunderstorms. High: 25Low: 15\n<BR /> Sun - Thunderstorms. High: 28Low: 21\n<BR /> Mon - Partly Cloudy. High: 24Low: 17\n<BR /> Tue - Partly Cloudy. High: 26Low: 18\n<BR />\n<BR />\n<a href=\"http://us.rd.yahoo.com/dailynews/rss/weather/Country__Country/*https://weather.yahoo.com/country/state/city-23511893/\">Full Forecast at Yahoo! Weather</a>\n<BR />\n<BR />\n(provided by <a href=\"http://www.weather.com\" >The Weather Channel</a>)\n<BR />\n]]>";

var re = /(alt|title|src)=("[^"]*")/gi;
var m;
while(m = re.exec(complicatedString)) {
console.log(m[2]);
}


我建议您使用以下正则表达式

/img.*?src=("|')(.*?)\1/i;

var complicatedString = "<![CDATA[<img src=\"http://l.yimg.com/a/i/us/we/52/32.gif\"/>\n<BR />\n<b>Current Conditions:</b>\n<BR />Sunny\n<BR />\n<BR />\n<b>Forecast:</b>\n<BR /> Fri - Sunny. High: 23Low: 13\n<BR /> Sat - Thunderstorms. High: 25Low: 15\n<BR /> Sun - Thunderstorms. High: 28Low: 21\n<BR /> Mon - Partly Cloudy. High: 24Low: 17\n<BR /> Tue - Partly Cloudy. High: 26Low: 18\n<BR />\n<BR />\n<a href=\"http://us.rd.yahoo.com/dailynews/rss/weather/Country__Country/*https://weather.yahoo.com/country/state/city-23511893/\">Full Forecast at Yahoo! Weather</a>\n<BR />\n<BR />\n(provided by <a href=\"http://www.weather.com\" >The Weather Channel</a>)\n<BR />\n]]>";

var regex = /img.*?src=("|')(.*?)\1/i;
var match = complicatedString.match(regex)[2];
console.log(match);

关于javascript - 使用正则表达式从字符串中提取图像 url,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37751281/

27 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com