java - 添加指向 REST 响应的链接

Question

我有 REST 服务，可以使用未编码的域实体进行响应。例如:

Request:
GET http://someAddress.com/customer/001

Response:
<customer>
    <id>001</id>
    <name>Some Guy</name>
    ...
</customer>

我想添加一些链接到发现服务的响应。例如:

<customer>
    <id>001</id>
    <name>Some Guy</name>
    ...
    <link xml:link="delete" href="http://someAddress.com/customer/001"/>
</customer>

我担心的是这是否会导致编码问题。我希望链接可发现，但我希望消费者可以轻松使用域模式，它不包含链接元素。

将链接放在回复中的其他地方是否更好？如果有，在哪里？

Answer 1

假设您将 JAXB 用于对象到 XML 层，您可以使用 XmlAdapter 执行类似以下操作，但您需要一个用于链接的对象而不是字符串:

import java.net.HttpURLConnection;
import java.net.URL;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.annotation.adapters.XmlAdapter;

public class CustomerAdapter  extends XmlAdapter<String, Customer>{

    private JAXBContext jaxbContext;

    public CustomerAdapter() {
        try {
            jaxbContext = JAXBContext.newInstance(Customer.class);
        } catch(JAXBException e) {
            throw new RuntimeException(e);
        }
    }

    @Override
    public String marshal(Customer v) throws Exception {
        if(null == v) {
            return null;
        }
        return "http://someAddress.com/customer/" + v.getId();
    }

    @Override
    public Customer unmarshal(String v) throws Exception {
        if(null == v) {
            return null;
        }

        URL url = new URL(v);
        HttpURLConnection connection = (HttpURLConnection) url.openConnection();
        connection.setRequestMethod("GET");
        connection.setRequestProperty("Accept", "application/xml");

        Customer customer = (Customer) jaxbContext.createUnmarshaller().unmarshal(connection.getInputStream());
        connection.disconnect();
        return product;
    }

}

有关 XmlAdapter 的更多信息，请参阅:

• http://bdoughan.blogspot.com/2010/07/xmladapter-jaxbs-secret-weapon.html