gpt4 book ai didi

Swift Segue 从 UIBarButtonItem

转载 作者:行者123 更新时间:2023-11-30 11:53:25 28 4
gpt4 key购买 nike

我以前做过很多次转场,但从来没有从 UIBarButtonItem 开始转场。

我就是不明白这到底出了什么问题。我不断收到同样的错误。 libc++abi.dylib:以 NSException 类型的未捕获异常终止。

我不想用这个segue传递任何数据,只是显示 Controller 。

我做错了什么??????

                let badge = UILabel(frame: CGRect(x: 20, y: 10, width: 20, height: 20))
badge.layer.borderColor = UIColor.clear.cgColor
badge.layer.borderWidth = 2
badge.layer.cornerRadius = badge.bounds.size.height / 2
badge.textAlignment = .center
badge.layer.masksToBounds = true
badge.textColor = .white
badge.font = UIFont(name: "AppleSDGothicNeo-Medium", size: 12)
badge.backgroundColor = .red
badge.text = "\(snapshot.childrenCount.description)"

let navBarFollowBtn = UIButton(frame: CGRect(x: 0, y: 0, width: 35, height: 35))
navBarFollowBtn.setImage(UIImage(named: "profileNewFollower"), for: .normal)
navBarFollowBtn.addTarget(self, action: Selector(("navigateToNextViewController")), for: UIControlEvents.touchUpInside)

navBarFollowBtn.addSubview(badge)

let barBtn = self.navBarNewFollower
barBtn?.customView = navBarFollowBtn
self.navigationItem.leftBarButtonItem = barBtn
// self.performSegue(withIdentifier: "newFollowerSegue", sender: self)

} else {

self.navBarNewFollower.isEnabled = true
}
})
}

setUpBadgeCountNewFollowers()

//Segue to NewFollowers
func navigateToNextViewController() {
print("Button Tapped")
self.performSegue(withIdentifier: "newFollowerSegue", sender: self)

}

最佳答案

您的选择器中有双括号,我猜这就是问题所在:

        navBarFollowBtn.addTarget(self, action: Selector(("navigateToNextViewController")), for: UIControlEvents.touchUpInside)

对于 swift 4 将其更改为:

navBarFollowBtn.addTarget(self, action: #selector(navigateToNextViewController), for: .touchUpInside)

@objc func navigateToNextViewController() {
print("Button Tapped")
self.performSegue(withIdentifier: "newFollowerSegue", sender: self)
}

关于Swift Segue 从 UIBarButtonItem,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48100925/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com