javascript - 如何通过在 google apps 脚本中使用其名称来获取 Gsheet 文件的 ID

Question

我正在拔头发。我有以下代码，并且一直在尝试弄清楚如何使用其名称获取 gsheet 文件的 ID。我的目标是按名称查找文件，然后获取 ID，然后从该文件中获取一个范围并将其输出到事件工作表中

function onOpen() {
  var ui = SpreadsheetApp.getUi();
  // Or DocumentApp or FormApp.
  ui.createMenu('Master Analysis Functions')
  .addItem('Update Sheet', 'updateSheet')
  .addSeparator()
  .addSubMenu(ui.createMenu('Test Menu')
              .addItem('Test Function', 'menuItem2'))
  .addToUi();
}

function updateSheet() {
  
  /* Top Level Google Drive Folder ID & General Settings */
  var TopDrivefolderId = "0B2rN5b8fW77ldXZXOXFLZGlSamc";
  var BaseNumberOfFilesInFolder = 5;
  var filesInFolderBeforeTemplate = 4;
  /* End General Settings */
  
  var parentFolder = DriveApp.getFolderById(TopDrivefolderId);
  var childFolders = parentFolder.getFolders();
  
  while(childFolders.hasNext()) {
    var child = childFolders.next();
    //    Logger.log(child.getName() + " |Drive_ID: " + child.getId());
    var folderId = child.getId();
    // **the folderId Variable is also the folder ID,
    //    hence they are used interchangeably **   
    
    var myFolder = DriveApp.getFolderById(folderId);
    
    /* Name of combined Spreadsheet*/
    //var tradeName = Drive App.getFolderById(folderId).getName();
    var tradeName = DriveApp.getFolderById(folderId).getName();
    
    /* Get all spreadsheets that resided on that folder */
    var spreadSheets = myFolder.getFilesByType("application/vnd.google-apps.spreadsheet");
    var spreadSheetName = myFolder.getName();
    
    /* Check if a file needs to be created or if one already exists*/  
    var theFolder = DriveApp.getFolderById(folderId);
    var files = theFolder.getFiles();
    var fname = theFolder.getName();
    
    var cnt = 0;
    var file;
    
    /* Check the quantity of files in a folder to see if you need to combine the sheets and create a file*/  
    while (files.hasNext()) {
      cnt++;
      file = files.next();
      //Logger.log(file.getName());
      if (cnt > BaseNumberOfFilesInFolder) {
        Logger.log("File already exists")
        break;
      } 
      ;
    };
    
    // If a file needs to be created this checks it and creates it
    Logger.log(cnt + " is the number of files '"+ tradeName+ "' has.");
    if (cnt > BaseNumberOfFilesInFolder){     
      Logger.log("The Data for " +tradeName+ " is already in the sheet.")
    } else if(cnt == filesInFolderBeforeTemplate){
      Logger.log("ERROR: You need to run the template adder script to add the template to " +tradeName)
      var sheet = SpreadsheetApp.getActiveSheet();
      sheet.appendRow(["ERROR: You need to run the template adder script to add the template to " +tradeName]);
      continue;
    }else{
      /* Create the new spreadsheet to verify this trade is in the master sheet */ 
      var newSpreadSheet = SpreadsheetApp.create("Added to Master");
  
      var spreadSheet = DriveApp.getId(tradeName);
      Logger.log(spreadSheet);


      Logger.log(tradeName + " It has been logged");
     
      var sheetCurrent = SpreadsheetApp.getActiveSheet();
      //sheetCurrent.appendRow([tradeName,data]);
      
      
      /* In order to move the file to the folder we want and because 
      google considers the SpreadSheet a Google Spreadsheet
      instead of a file, we have to convert the SpreadSheet to a file in
      order to move it.Thats what the next 2 lines of code do.*/
      var getNewSSid = newSpreadSheet.getId();
      var SStoGFile = DriveApp.getFileById(getNewSSid);
      /* Actually moving the file*/
      DriveApp.getFolderById(folderId).addFile(SStoGFile);
      
      /* Deleting the duplicate file that was created in the process*/
      var rootFolder = DriveApp.getRootFolder();
      DriveApp.getRootFolder().removeFile(SStoGFile);
      
    }  
    getSubFolders(child); 
    
  };
  
  SpreadsheetApp.getUi() // Or DocumentApp or FormApp.
  .alert('All Trades updated! Please check the sheet for errors.');
  
};  

function getSubFolders(parent) {
  parent = parent.getId();
  var childFolder = DriveApp.getFolderById(parent).getFolders();
  while(childFolder.hasNext()) {
    var child = childFolder.next();
    Logger.log(child.getName());
    getSubFolders(child);
  }
  return;
}
/* End iterate through Sub Folders */



function menuItem2() {
  
  var files = DriveApp.searchFiles("tradeName");
  Logger.log(files,tradeName);
  var spreadsheet = SpreadsheetApp.open(tradeName);
  var sheet = spreadsheet.getSheets()[0];
  Logger.log(sheet.getName());
  
  
  
  SpreadsheetApp.getUi() // Or DocumentApp or FormApp.
  .alert('You clicked the second menu item!');
};

.

Answer 1

你的代码有点太乱了，我无法真正找到你的问题所在以及你试图用它完成什么，但是根据你的问题本身，你需要做的是

fileList = DriveApp.getFilesByName('This_name')
while (fileList.hasNext()) {
  Logger.log(fileList.next().getId())
}

这将记录与该名称匹配的每个文件 ID。电子表格服务只能通过 ID 打开，因此您需要使用驱动器服务(我的意思是 google-spreadsheet 标签不适合这里，因为它只能作为驱动器处理)。

如果您想从电子表格服务中获取文件，您可以随时执行 SpreadsheetApp.open(fileList.next()) 直接从文件对象中打开它