Swift 2.0 和 3.0 中的 Json 解析

Question

我们在 swift 解析 JSON 时遇到问题。如果您查看示例图像，您就会看到我们的问题。我们从 json 中获取字符串。当我们分配给dictionary2时，我们得到异常:

"Could not cast value of type '__NSArrayM' (0x10652de00) to 'NSDictionary' (0x10652e2d8)."

我们如何解析这个？我们无法将 swift 更新到最新版本。

let urlJsonToken2 = "https://jsonservices.mywebsite.com/api/en/News"
let myURL2 = NSURL(string: urlJsonToken2)
let request2 = NSMutableURLRequest(url: myURL2 as! URL)
request2.httpMethod = "GET"
request2.addValue("Bearer "+token!, forHTTPHeaderField: "Authorization")
request2.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "content-type")
request2.setValue("application/json", forHTTPHeaderField: "Accept")
let task2 = URLSession.shared.dataTask(with: request2 as URLRequest) {(data2, response2, error2) -> Void in
    if let unwrappedData2 = data2 {
        do {
            let requestReply = NSString(data: data2!, encoding: String.Encoding.ascii.rawValue)
            let tokenDictionary2:NSDictionary = try JSONSerialization.jsonObject(with: unwrappedData2, options: JSONSerialization.ReadingOptions.mutableContainers) as! NSDictionary
            let Name = tokenDictionary2["Name"] as? String
        }
        catch {}
    }
}
task2.resume()

Answer 1

该错误告诉您您正在尝试将数组解析为字典。

let task2 = URLSession.shared.dataTask(with: request2 as URLRequest) {(data2, response2, error2) -> Void in
    if let unwrappedData2 = data2 {
        do {
            guard let records = try? JSONSerialization.jsonObject(with: unwrappedData2, options: .mutableContainers) as? [[String: Any]] else {
                print("[DEBUG] - Unable to parse JSON as array")
                return
            }

            let firstRecord = records.first
            print(records.count, firstRecord)

        } catch {}
    }
}

注意:使用 Swift 时，除非确实必要，否则应避免使用 NS 类。 Swift 有它自己的桥接类型。 NSDictionary = 字典，NSArray = 数组