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java - 如何处理从 Java 客户端上传的服务器端 HTTP 文件

转载 作者:行者123 更新时间:2023-11-30 11:46:48 25 4
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我想从客户端上传文件到服务器。

客户端:Java 使用 HTTP post服务器:Java Servlet

我在这里添加了客户端编码。但是,我对服务器端处理一无所知。请帮我做一个代码片段。

 private String Tag = "UPLOADER";
private String urlString = "http://192.168.42.140:8080/sampweb";
HttpURLConnection conn;
String exsistingFileName = "/sdcard/log.txt";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
try {
// ------------------ CLIENT REQUEST

Log.e(Tag, "Inside second Method");

FileInputStream fileInputStream = new FileInputStream(new File(
exsistingFileName));

// open a URL connection to the Servlet

URL url = new URL(urlString);

// Open a HTTP connection to the URL

conn = (HttpURLConnection) url.openConnection();

// Allow Inputs
conn.setDoInput(true);

// Allow Outputs
conn.setDoOutput(true);

// Don't use a cached copy.
conn.setUseCaches(false);

// Use a post method.
conn.setRequestMethod("POST");

conn.setRequestProperty("Connection", "Keep-Alive");

conn.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);

DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

dos.writeBytes(twoHyphens + boundary + lineEnd);
dos
.writeBytes("Content-Disposition: post-data; name=uploadedfile;filename="
+ exsistingFileName + "" + lineEnd);
dos.writeBytes(lineEnd);

Log.e(Tag, "Headers are written");

// create a buffer of maximum size

int bytesAvailable = fileInputStream.available();
int maxBufferSize = 1000;
// int bufferSize = Math.min(bytesAvailable, maxBufferSize);
byte[] buffer = new byte[bytesAvailable];

// read file and write it into form...

int bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);

while (bytesRead > 0) {
dos.write(buffer, 0, bytesAvailable);
bytesAvailable = fileInputStream.available();
bytesAvailable = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);
}

// send multipart form data necessary after file data...

dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

// close streams
Log.e(Tag, "File is written");
fileInputStream.close();
dos.flush();
dos.close();

} catch (MalformedURLException ex) {
Log.e(Tag, "error: " + ex.getMessage(), ex);
}

catch (IOException ioe) {
Log.e(Tag, "error: " + ioe.getMessage(), ioe);
}

try {
BufferedReader rd = new BufferedReader(new InputStreamReader(conn
.getInputStream()));
String line;
while ((line = rd.readLine()) != null) {
Log.e("Dialoge Box", "Message: " + line);
}
rd.close();

} catch (IOException ioex) {
Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
}
}

我是服务器编程的新手。如果我犯了任何错误,请澄清我。谢谢!

最佳答案

实现此目标的最佳库仍然是 Apache Commons File Upload .它有据可查且易于使用。如果您遇到任何问题,请检查 FAQ首先。

关于java - 如何处理从 Java 客户端上传的服务器端 HTTP 文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9615441/

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