Swift:带有 inout 闭包的函数

Question

我有以下结构:

struct MyStruct {
    var myInt: Int
    var myString: String
}

应该在如下函数中编辑该结构:

func editMyStruct(action: (inout MyStruct) -> ()) {
    var mutableMyStruct = MyStruct(myInt: 10, myString: "Foo")
    action(&mutableMyStruct)
    //do something with the modified 'mutableMyStruct' ...
}

但是，我确实很难调用 editMyStruct(action: (inout MyStruct) -> ())。

editMyStruct(action: { myStruct in
    myStruct.myInt = 20
    myStruct.myString = "Bar"
})

XCode 抛出错误:

Type of expression is ambiguous without more context

你们有人知道如何解决这个问题吗？

期待您的回复!

Answer 1

找到答案了!

editMyStruct(action: (inout MyStruct) -> ()) 的语法必须是:

editMyStruct(action: { (myStruct: inout MyStruct) in
    myStruct.myInt = 20
    myStruct.myString = "Bar"
})

编辑

啊啊!我真丢脸。我注意到由于具有相同签名的另一个函数而引发了上述错误...上面的代码很好;)