ios - 如何在 Swift 4 中多次点击 UIButton 以将不同的字符串打印回 outputLabel？目标是创建 T9 文本

Question

我在尝试让 UI 按钮进行多次点击时遇到问题，我知道这并不理想，但如果有人可以告诉我我做错了什么或为我指出正确的方向，那就太好了。下面是我当前的代码，我正在尝试创建一个名为“twoPressed”的函数，该函数根据点击的次数进行响应。

var resultOfLabel = ""

@IBOutlet weak var outputLabel: UILabel!

override func viewDidLoad() {
    super.viewDidLoad()

    let tapGesture1 = UITapGestureRecognizer(target: self, action: #selector(singleTap(gesture:)))
    UIButton.addGestureRecognizer(tapGesture1)

    let tapGesture2 = UITapGestureRecognizer(target: self, action: #selector(doubleTap(gesture:)))
    tapGesture2.numberOfTapsRequired = 2
   UIButton.addGestureRecognizer(tapGesture2)

    let tapGesture3 = UITapGestureRecognizer(target: self, action: #selector(tripleTap(gesture:)))
    tapGesture3.numberOfTapsRequired = 3
    UIButton.addGestureRecognizer(tapGesture3)

    let tapGesture4 = UITapGestureRecognizer(target: self, action: #selector(quadrupleTap(gesture:)))
    tapGesture4.numberOfTapsRequired = 4
    UIButton.addGestureRecognizer(tapGesture4)

    // Do any additional setup after loading the view.
}

@IBAction func twoPressed(sender: UIButton) {

   @objc func singleTap() {
        print(“2”)
    }

   @objc func doubleTap() {
        print(“a”)
    }

   @objc func tripleTap() {
        print(“b”)
    }

  @objc func quadrupleTap() {
        print(“c”)
    }

    resultOfLabel += "\(sender)"

    outputLabel.text = resultOfLabel

}

Answer 1

除了从IBAction方法中获取这4个函数之外没有问题

let tapGesture1 = UITapGestureRecognizer(target: self, action: #selector(self.singleTap(_:)))
UIButton.addGestureRecognizer(tapGesture1)

//

@objc func singleTap(_ sender: UITapGestureRecognizer? = nil) {
    print(“2”)
   self.twoPressed(sender.View as! UIButton)
}

@objc func doubleTap() {
    print(“a”)
}

@objc func tripleTap() {
    print(“b”)
}

@objc func quadrupleTap() {
    print(“c”)
}


 @IBAction func twoPressed(sender: UIButton) {

  resultOfLabel += "\(sender)"
  outputLabel.text = resultOfLabel

 }