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javax.命名.NamingException : Cannot create resource instance

转载 作者:行者123 更新时间:2023-11-30 11:44:56 27 4
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我已经尝试了下面的大量变体来使数据源工作但无济于事。我已经研究/尝试了几天,所以我认输并寻求帮助。不过首先,我很难在这篇文章中格式化我的代码。没有缩进,某些 xml 标记正在消失。可能是愚蠢的 IE 迫使我们使用....

web.xml

<resource-ref>
<res-ref-name>jdbc/nalabor</res-ref-name>
<res-type>oracle.jdbc.pool.OracleDataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>

<resource-ref>
<res-ref-name>jdbc/navarch</res-ref-name>
<res-type>oracle.jdbc.pool.OracleDataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>

上下文.xml

<?xml version="1.0" encoding="UTF-8"?>

<Context>
<Resource
name="jdbc/nalabor" type="oracle.jdbc.pool.OracleDataSource"
maxActive="1" maxIdle="1" maxWait="10000"
factory="oracle.jdbc.pool.OracleDataSourceFactory"
url="jdbc:oracle:thin:@####.com:1521:SID"
driverClassName="oracle.jdbc.driver.OracleDriver"
username="###" password="###"/>

<Resource
name="jdbc/navarch" type="oracle.jdbc.pool.OracleDataSource"
maxActive="1" maxIdle="1" maxWait="10000"
factory="oracle.jdbc.pool.OracleDataSourceFactory"
url="jdbc:oracle:thin:@####.com:1521:SID"
driverClassName="oracle.jdbc.driver.OracleDriver"
username="###" password="###"/>
</Context>

try {      
Context initContext = new InitialContext();
NamingEnumeration list = initContext.list("java:/comp/env");
System.out.println("Listing NamingEnumeration For java:/comp/env");
while (list.hasMore()) {
NameClassPair nc = (NameClassPair)list.next();
System.out.println("Name Class Pair = " + nc);
}

list = initContext.list("java:/comp/env/jdbc");
System.out.println("Listing NamingEnumeration java:/comp/env/jdbc");
while (list .hasMore()) {
NameClassPair nc = (NameClassPair)list .next();
System.out.println("Name Class Pair = " + nc);
}

Context envContext = (Context) initContext.lookup("java:/comp/env");
ods = (OracleDataSource) envContext.lookup("jdbc/nalabor");
} catch (Exception ex) {
System.out.println("ERORRRRRRRR AGAIN!");
ex.printStackTrace();
}

堆栈

Listing NamingEnumeration For java:/comp/env
Name Class Pair = mailClient: java.lang.String
Name Class Pair = siteConnCache: java.lang.String
Name Class Pair = jdbc: org.apache.naming.NamingContext
Name Class Pair = sitePOCEmail: java.lang.String
Name Class Pair = siteFilePrefix: java.lang.String
Name Class Pair = siteName: java.lang.String
Name Class Pair = siteEmail: java.lang.String

Listing NamingEnumeration java:/comp/env/jdbc
Name Class Pair = nalabor: org.apache.naming.ResourceRef
Name Class Pair = navarch: org.apache.naming.ResourceRef
ERORRRRRRRR AGAIN!
javax.naming.NamingException: Cannot create resource instance
at org.apache.naming.factory.ResourceFactory.getObjectInstance(ResourceFactory.java:167)
at javax.naming.spi.NamingManager.getObjectInstance(NamingManager.java:314)
at org.apache.naming.NamingContext.lookup(NamingContext.java:834)
at org.apache.naming.NamingContext.lookup(NamingContext.java:181)
at org.apache.naming.NamingContext.lookup(NamingContext.java:822)
at org.apache.naming.NamingContext.lookup(NamingContext.java:194)
at com.gdebI.rozycki.bsc.data.LaborDAO.getWeightedLabor(LaborDAO.java:91)
at com.gdebI.rozycki.bsc.controller.action.WeightedLabor.getList(WeightedLabor.java:66)
at com.gdebI.rozycki.controller.action.ListAction.service(ListAction.java:38)

WEB-INF/lib

ojdbc14.jar

最佳答案

我不确定您为什么在 web.xml 中列出您的资源,但我认为您包含了导致问题的额外/。当找不到名称时,我遇到了这个异常。试试这个(Java 6+):

OracleDataSource ods = InitialContext.doLookup("java:comp/env/jdbc/nalabor");

或者对于 Java 5 及以下版本:

InitialContext ic = new InitialContext();
OracleDataSource ods = (OracleDataSource)ic.lookup("java:comp/env/jdbc/nalabor");

关于javax.命名.NamingException : Cannot create resource instance,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10534826/

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