swift - 无法从解码器获取字典

Question

我需要将整个字典作为键“内容”的字符串获取。我收到的它为零。我尝试使用 [String:Any] 抛出异常，任何内容都无法确认为可解码

public static func getModelObjects<R: Codable>(_ type: R.Type, from data: Any?) -> [T]? {
        var mappedObjects: [T]?
        if let dataAsDic = data as? JSONDictionary {
            let decodedObject = decodableData(type, dictionaryData: dataAsDic)
            mappedObjects = [decodedObject] as? [T]
        } else if let dataAsArray = data as? [JSONDictionary] {
            var objects: [R] = []
            for dataAsDic in dataAsArray {
                guard let decodedObject = decodableData(type, dictionaryData: dataAsDic) else {
                    return nil
                }
             objects.append(decodedObject)
            }
            mappedObjects = objects as? [T]
        }
        return mappedObjects
    }

    private static func decodableData<R: Codable>(_ type: R.Type, dictionaryData: JSONDictionary) -> R? {
            let decoder = JSONDecoder()
            do {
                let jsonData = try JSONSerialization.data(withJSONObject: dictionaryData, options: JSONSerialization.WritingOptions.prettyPrinted)
                let decodedData = try decoder.decode(type, from: jsonData)
                return decodedData
            } catch {
                return nil
            }
        }

    public class Configuration: CacheableEntity, ConfigurationStorageProtocol, Codable {
          public dynamic var configurationID: String!

            /// Version of configuration
            public dynamic var version: String!

            private var storedConfigDict: JSONDictionary?

            private var storedConfigData: Data?
              // Holds complete configuration as string

    dynamic var configString: String? 

                /// Codable keys to confirm Codable protocol
                private enum CodingKeys: String, CodingKey {
                    case configurationID = "id"
                    case version
                    case name
                    case content
                }

            public required init(from decoder: Decoder) throws {
                super.init()
                let container = try decoder.container(keyedBy: CodingKeys.self)
                self.name = try? container.decode(String.self, forKey: .name)
                self.configurationID = try? container.decode(String.self, forKey: .configurationID)
                self.version = try? container.decode(String.self, forKey: .version)
                self.configString = try? container.decode(String.self, forKey: .content)
            }

public func encode(to encoder: Encoder) throws {
    var  container = encoder.container(keyedBy: CodingKeys.self)
    try? container.encode(configurationID, forKey: .configurationID)
    try? container.encode(version, forKey: .version)
    try? container.encode(name, forKey: .name)
  }
}

在下面的 json 中，我需要以字符串形式获取整个内容。我尝试过使用 [String:Any]，但它崩溃了，因为任何内容都无法符合可解码的要求。

"name": "sdkconfig",
    "id": "gma_5.0_ios_sdkconfig_1.0_us",
    "version": "1.0",
    "modifiedDateTime": "2017-06-15T08:15:25.304Z",
    "content": {
        "configName": "sdkConfig",
        "configVersion": "1.0",
        "enabled": {
            "modules": [
                        "account",
                        "nutrition",
                        "restaurant",
                        "offer",
                        "ordering",
                        "favorite"
                        ],
            "socialAccounts": [
                               "facebook",
                               "google",
                               "twitter"
                               ]
        }
}

Answer 1

我不确定你的做法。但这就是我让它发挥作用的方式。像这样定义你的类。

    struct Configuration: Codable {

        var content: String?
    }

属性名称和json中的名称必须相同。 (在本例中为“内容”)。现在解析你的 json 字符串，如下所示。

    var configuration = JSONDecoder().decode(Configuration.self, from: "your json string")