arrays - 在 if 语句中过滤带有空字符串的字符串，iOS

Question

我正在开发自定义键盘。我在过滤字符串数组时遇到问题。我只想在 if 语句中过滤数组，我有一个包含字母和空字符串的数组。我只想在 if 语句中过滤数组，因为我想删除最后一个字符，而不是空字符串。

这是我的代码:

keyboardKeyStr = ["h", "e", "l", "l", "o", " ", "", "t", "h", "i", "s", "", "i", "s", " ", "m", "y", " ", "", "a", "r", "r", "a", "y", " "]

if range.length == 1 && text.count == 0 {
    print("Delete Button")

    let emptyStr: String? = ""
    keyboardKeyStr = keyboardKeyStr.filter {$0 != emptyStr}
    keyboardKeyStr.removeLast()
    keyboardKeyArr.append(keyboardView.deleteBtn)
    self.keyboardKeyStr.append("")
}

Answer 1

试试这个keyboardKeyStr = KeyboardKeyStr.filter{ $0 != ""&& $0 != ""}