ios - Swift:返回json数据

Question

这个问题已经有答案了:

Returning data from async call in Swift function (13 个回答)

已关闭 5 年前。

我从 url 获取 json 数据，我想从函数返回到变量并再次使用它

internal func getJson(urlGet:String, urlData:String){
    let urlFind = URL(string: urlGet)
    var request = URLRequest(url: urlFind!)
    request.httpMethod = "POST"
    request.httpBody = urlData.data(using: .utf8)

    var firstDataGet = [firstData]()

    URLSession.shared.dataTask(with:request, completionHandler: {(data, response, error) in
        guard let data = data, error == nil else { return }
        print(urlGet)

        do {
            let json = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as! [String:String]
            print(json)

        } catch let error as NSError {
            json = nil
        }
    }).resume()

    return json
}

以及 View Controller 的用法:

let result = getJsonLogin.getJson(urlGet: AppDelegate.ADDRESS+"/index.php", urlData: "mobile="+mobile+"")
print(result["message"])

我是初学者，我无法解决这个问题

Answer 1

URLSession 请求是异步的。

因此您需要设置回调来检索数据。就像这样:

internal func getJson(urlGet: String, urlData: String, completion: @escaping ([String:String]?) -> Void) {
    let urlFind = URL(string: urlGet)
    var request = URLRequest(url: urlFind!)
    request.httpMethod = "POST"
    request.httpBody = urlData.data(using: .utf8)

    var firstDataGet = [firstData]()

    URLSession.shared.dataTask(with:request, completionHandler: { (data, response, error) in
        guard let data = data, error == nil else { return }
        print(urlGet)

        do {
            let json = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as! [String:String]
            print(json)
            completion(json)

        } catch let error as NSError {
            json = nil
            completion(nil)
        }
    }).resume()
}


let result = getJsonLogin.getJson(urlGet: AppDelegate.ADDRESS+"/index.php", urlData: "mobile="+mobile+"") { result in
    print(result)
}

当然，您可以(并且可能应该)比仅仅传递 nil 更正确地处理错误。但为了简单起见，我只是添加了我能想到的最简单的方法来解决您的问题。