ios - 如何在 CXAnswerCallAction 之后推送 View Controller

Question

一旦用户使用 CallKit 接听电话，我就会尝试显示特定的 View Controller 。目前，在 CXAnswerCallAction 中我尝试使用:

if UIApplication.shared.canOpenURL(URL(string: "URLgoesHERE://")!) {
UIApplication.shared.openURL(URL(字符串: "URLgoesHERE://")!)
}//替换我的问题的 URL 架构


但我收到以下错误:

URL 失败:“URLgoesHERE://” - 错误:“此应用程序不允许查询方案 URLgoesHERE”


还有其他想法吗？

Answer 1

您是否将 URL 方案添加到 info.plist 内的 LSApplicationQueriesSchemes 键中？

LSApplicationQueriesSchemes (Array - iOS) Specifies the URL schemes you want the app to be able to use with the canOpenURL: method of the UIApplication class. For each URL scheme you want your app to use with the canOpenURL: method, add it as a string in this array. Read the canOpenURL: method description for important information about declaring supported schemes and using that method.

来源:https://developer.apple.com/library/content/documentation/General/Reference/InfoPlistKeyReference/Articles/LaunchServicesKeys.html#//apple_ref/doc/uid/TP40009250-SW14