javascript - Angular 2 : Directives: capturing click event on children

Question

我知道这一定很简单，但今天 - 星期一无法理解 :)

所以，我有一个响应式表格的指令

import {Directive, HostListener} from '@angular/core';

@Directive({
    selector: '.table-responsive'
})
export class TableResponsiveDirective {

    @HostListener('click', ['$event']) scroll(direction: string, event: MouseEvent){
        console.info('clicked: ' + direction + ' ' +event);
        event.stopPropagation();
        event.preventDefault();
    }
}

这是我的看法

<div class="table-responsive">
    <a href="#" (click)="scroll('left', $event)">LEFT</a>
    <a href="#" (click)="scroll('right', $event)">RIGHT</a>
    <table>...</table>
</div>

现在，我该如何让它发挥作用？我不想捕获整个 .table-responsive... 但只是那两个链接

Answer 1

不想深入，但这对您来说是一个快速的解决方案。尝试用事件绑定(bind)你的左，右信息，像这样用事件绑定(bind)它里面

<div class="table-responsive">
 <a href="#" (click)="$event.left = true">LEFT</a>
 <a href="#" (click)="$event.right = true">RIGHT</a>
 <table>...</table>
</div>

像这样提取

import {Directive, HostListener} from '@angular/core';

@Directive({
 selector: '.table-responsive'
})
export class TableResponsiveDirective {

 @HostListener('click', ['$event'])
 scroll($event){
    if ($event.left) {
     console.info('clicked: ' + $event.left);
    } else if ($event.right) {
     console.info('clicked: ' + $event.right);
    }
    event.stopPropagation();
    event.preventDefault();
 }
}

在这种情况下，您可以通过事件对象中的左、右标志简单地知道方向并添加您的代码:)