javascript - node.js 文件中的单独函数

Question

我想在我的 node.js 文件中分离函数。我不知道该怎么做。

这是一个例子:

    var var1 = 'I want to use this var along across all included files';
    var var2 = 'I want to use this var along across all included files';
    var actions = {
        send1() { //function 1 with var1 & var2 },
        send1a() { //function 1a with var1 & var2},
        send2() { //function 2 with var1 & var2},
        send2a() { //function 2a with var1 & var2}
    };

我想在 function1.js 和 send2() 中导出 send1() & send1a() & function2.js 中的 send2a() 以获得干净的文件并使用 var1 & var2。

我怎样才能正确地做到这一点？

Answer 1

创建 2 个模块文件:fun1.js

var var1 = "CONSTANT"


var actions = {
    // Whatever you want to export, you can write it here
    send1: function () {
        console.log("send1", var1)
    },
    send1a: function () {
        console.log("send1a")
    },
    a: "asdsad",
    b: 45,
    c: [1, 2, 3, 4, 5, 6],
    var1: var1
}


module.exports = actions

/*
 Or you can export using
 module.exports = {
     actions: actions,
     variableX: "something"
 }

 then in other modules, import it as
 var fun = require('./module_path')

 And use it as fun.variableX, fun.actions.send1 etc
 */

fun2.js

// Import variable from other module
var fun1 = require('./fun1')
// or just import var1
// var var1 = require('./fun1').var1

var actions = {
    send2: function () {
        console.log("send2", fun1.var1)
    },
    send2a: function () {
        console.log("send2a")
    }
}


module.exports = actions

然后在主文件中

主要.js

// Import all modules
var fun1 = require('./fun1')
var fun2 = require('./fun2')

console.log(fun1.a) // Prints array

// fun1 will have all exported modules from fun1.js file
fun1.send1() // Prints send1 CONSTANT
fun1.send1a()

// fun2 will have all exported modules from fun2.js file
fun2.send2()  // Prints send2 CONSTANT
fun2.send2a()