java - 运行服务时 Activity 卡住

Question

我有一个按钮，当按下它时，它会启动一项服务。该服务开始从设备记录信息。但是，当我按下运行时，屏幕在记录时会暂时卡住大约 8 秒，然后一旦完成屏幕就会解冻，显示一条提示消息(这意味着一旦你按下按钮就会显示)然后我可以为所欲为。如果我再次进入应用程序屏幕，当应用程序正在记录时(注意:服务始终在运行，因此不会卡住它，只是记录)然后 Activity 将再次卡住并且在记录完成之前不会让我做任何事情。

我尝试过异步任务并在新的可运行/新线程上运行，但这些似乎都不适合我。我不确定是否正确实现了它们，但我想解决这个问题。

这是我在服务类中的 onStartCommand:

    @Override
public int onStartCommand(Intent intent, int flags, int startId) {
    // THIS WOULD BE THE METHOD THAT RUNS WHATEVER YOU WANT TO DO EVERY SO OFTEN SO FOR ME THIS IS GETTING ALL DATA ETC
    getProcessInfo();

    //  LOG DELAY = SECONDS BETWEEN RUNNING SERVICE/METHOD. SET AT THE TOP
    myPendingIntent = PendingIntent.getService(this, 0, intent, PendingIntent.FLAG_UPDATE_CURRENT);
    Alarmmgr.set(AlarmManager.RTC_WAKEUP, System.currentTimeMillis()+LOG_DELAY*1000, myPendingIntent);
    Intent notificationIntent = new Intent(this, LogOrCheck.class);
    PendingIntent contentIntent = PendingIntent.getActivity(this,
            101, notificationIntent,
            PendingIntent.FLAG_NO_CREATE);

    NotificationManager nm = (NotificationManager) this
            .getSystemService(Context.NOTIFICATION_SERVICE);

    Resources res = this.getResources();
    Notification.Builder builder = new Notification.Builder(this);

    builder.setContentIntent(contentIntent)
                .setSmallIcon(R.drawable.arrow_up_float)
                .setLargeIcon(BitmapFactory.decodeResource(getResources(), R.drawable.arrow_down_float))
                .setWhen(System.currentTimeMillis())
                .setAutoCancel(true)
                .setContentTitle("Androigenius")
                .setContentText("Service running OK");
    Notification n = builder.getNotification();


    startForeground(100, n);
    return Service.START_STICKY;
}

这里是我调用 startService 的地方:

but1.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {

            if (isClicked) {
                Context context = getApplicationContext();
                Toast toast = Toast.makeText(context, "Please press 'MINIMIZE' at the top to continue logging.", Toast.LENGTH_LONG);
                toast.setGravity(Gravity.TOP|Gravity.RIGHT, 10, 55);
                toast.show();
                System.out.println("Start logging");
                but1.setText("Stop Logging");
                but1.setTextColor(Color.RED);
                // START SERVICE, DONE. (STOP IS BELOW).
                startService(myIntent);
                isClicked = false;
            } 
            else if (!isClicked) {
                System.out.println("Stop Logging");
                but1.setText("Start Logging");
                // STOP SERVICE, DONE.
                stopService(myIntent);
                but1.setTextColor(getResources().getColor(color.cornblue));
                isClicked = true;
            }

Answer 1

服务在导致“卡住”的 UI 线程上运行。使用 IntentService 将创建一个自动在后台运行的服务，而不是在 UI 线程上。以下是 IntentService 类的一些细节:

IntentService Class