javascript - 重用通过解构创建的对象字面量

Question

我正在尝试为两个异步调用重用对象文字。最后，我的期望应该检查 deleteBucket 调用是否成功。问题是我不能这样做，或者它说我已经定义了重复变量:

it('can delete a bucket', async () => {
      const options = { branch: '11' }

      let { failure, success, payload } = await deployApi.createBucket(options)
      let { failure, success, payload} = await deployApi.deleteBucket(options.branch)

      expect(success).to.be.true
    })

有人告诉我我可以在第二个附近放一个 () ，但这给了我一个 TypeError: (0 , _context4.t0) is not a function 错误:

it('can delete a bucket', async () => {
  const options = { branch: '11' }

  let { failure, success, payload } = await deployApi.createBucket(options)

  ({ failure, success, payload} = await deployApi.deleteBucket(options.branch))

  expect(success).to.be.true
})

这确实有效，但需要我更改我不想做的已解析对象的名称:

it('can delete a bucket', async () => {
      const options = { branch: '11' }

      let { failure, success, payload } = await deployApi.createBucket(options)
      let { failure1, success1, payload1} = await deployApi.deleteBucket(options.branch)

      expect(success1).to.be.true
    })

更新:

有人建议我在 const 行之后需要一个分号。没有任何区别，当我运行它时我仍然得到同样的错误:

Answer 1

缺少分号

你有两个 (...) 排列在一起 -

await deployApi.createBucket(options)  

({ failure, success, payload} = await deployApi.deleteBucket(options.branch))

ES 解释器将其视为 -

await deployApi.createBucket(options)(... await deployApi.deleteBucket(options.branch))

相当于-

const r1 = deployApi.createBucket(options)
const r2 = r1(... await deployApi.deleteBucket(options.branch))
await r2

这与您的实际意图非常不同 -

const r1 = await deployApi.createBucket(...)
const r2 = await deployApi.deleteBucket(...)

要重用let解构对象，需要括号-

// initial assignment
let { a, b, c } = ...

// without the parentheses, ES interprets as illegal assignment using =
{ a, b, c } = ...

// with parentheses, ES interprets as destructuring assignment
({ a, b, c } = ...)

如果您重复使用相同的 let 绑定(bind)，则在不使用分号时，必需的 括号会改变程序的含义。

it('can delete a bucket', async () => {
  const options = { branch: '11' }
                                                           // semicolon here
  let { failure, success, payload } = await deployApi.createBucket(options); 
  
  ({ failure, success, payload} = await deployApi.deleteBucket(options.branch))
  
  expect(success).to.be.true
})