java - 使用 http post 登录网站

Question

我正在尝试创建一个应用程序以登录此网站 http://www.reclameaqui.com.br/当我输入登录名和密码时，应用程序会向我显示:

03-01 22:34:47.220: W/SENCIDE(27717): 403 禁止

禁止

您没有权限访问此服务器上的/areadoconsumidor/。

---

Apache/2.2.15 (CentOS) 服务器位于www.reclameaqui.com.br 端口80包 com.sencide;

这是代码

    package com.sencide;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;

import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;

import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

public class AndroidLogin extends Activity implements OnClickListener {

    Button ok,back,exit,site;
    TextView result;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

     // Login button clicked
        site = (Button)findViewById(R.id.button1);
        site.setOnClickListener(this);


        // Login button clicked
        ok = (Button)findViewById(R.id.btn_login);
        ok.setOnClickListener(this);

        result = (TextView)findViewById(R.id.lbl_result);

    }

    public void postLoginData() {
        // Create a new HttpClient and Post Header
        HttpClient httpclient = new DefaultHttpClient();

        /* logar no site */
        HttpPost httppost = new HttpPost("http://www.reclameaqui.com.br/includes/autenticaUsuario.php");

        try {
            // Add user name and password
            EditText uname = (EditText)findViewById(R.id.txt_username);
            String username = uname.getText().toString();

            EditText pword = (EditText)findViewById(R.id.txt_password);
            String password = pword.getText().toString();

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(6);
            nameValuePairs.add(new BasicNameValuePair("identificador", username ));
            nameValuePairs.add(new BasicNameValuePair("senha", password ));
            nameValuePairs.add(new BasicNameValuePair("urlRedir", "http://www.reclameaqui.com.br/areadoconsumidor/"));
            nameValuePairs.add(new BasicNameValuePair("tipo", "cadastro" ));
            nameValuePairs.add(new BasicNameValuePair("x", "35" ));
            nameValuePairs.add(new BasicNameValuePair("y", "24" ));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            // Execute HTTP Post Request
            Log.w("SENCIDE", "Execute HTTP Post Request");
            HttpResponse response = httpclient.execute(httppost);

            String str = inputStreamToString(response.getEntity().getContent()).toString();
            Log.w("SENCIDE", str);

            if(str.toString().equalsIgnoreCase("true"))
            {
                Log.w("SENCIDE", "TRUE");
                result.setText("Login successful");   
            }else
            {
                Log.w("SENCIDE", "FALSE");
                result.setText(str);                
            }

        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    } 

    private StringBuilder inputStreamToString(InputStream is) {
        String line = "";
        StringBuilder total = new StringBuilder();
        // Wrap a BufferedReader around the InputStream
        BufferedReader rd = new BufferedReader(new InputStreamReader(is));
        // Read response until the end
        try {
            while ((line = rd.readLine()) != null) { 
                total.append(line); 
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
        // Return full string
        return total;
    }

    @Override
    public void onClick(View view) {
        if(view == ok){
            postLoginData();
        }
    }

}

我该怎么做才能使应用程序运行良好？有人帮助我；

Answer 1

您好像发错页面了。

<form action="includes/autenticaUsuario.php" method="post" onsubmit="return valida_form(this)">

表单似乎发布到 http://www.reclameaqui.com.br/includes/autenticaUsuario.php .

它还有隐藏字段:<input type="hidden" name="urlRedir" value="http://www.reclameaqui.com.br/areadoconsumidor/">

和

<input type="hidden" name="tipo" value="cadastro">

其次，用户名输入命名为<input type="text" name="identificador">密码输入名为<input type="password" name="senha">所以我相信你的 BasicNamveValuePairs 应该更像这样:new BasicNameValuePair("identificador", identificador)和 new BasicNameValuePair("senha", senha)

---

它应该看起来像这样:

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(4);
nameValuePairs.add(new BasicNameValuePair("tipo", "cadastro"));
nameValuePairs.add(new BasicNameValuePair("urlRedir", "http://www.reclameaqui.com.br/areadoconsumidor/"));
nameValuePairs.add(new BasicNameValuePair("identificador", identificador));
nameValuePairs.add(new BasicNameValuePair("senha", senha));