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ios - 如何获取包含字典的数组

转载 作者:行者123 更新时间:2023-11-30 11:34:11 26 4
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我想让这个数组包含要传入api的字典。

请检查最后的参数结果,我得到“\n”

[{"user_id":"46","e_id":"566","date_list":"2018\/04\/20","t_depo":" 0.0","mini":"200","real_earn":"-5000.0","mb_balance":"-4000.0","balance_for":"4000"}]

有什么想法吗?

我尝试以这种方式在 api 上发送但没有成功

var ary : [[String:String]] = []
var mutableDictionary = [String: String]()
var mutableArray:NSMutableArray!

mutableDictionary.updateValue("\(appdel.dateSelected!)", forKey: "date_list")
mutableDictionary.updateValue("\(user_id)", forKey: "user_id")
mutableDictionary.updateValue("566", forKey: "e_id")
mutableDictionary.updateValue("\(RupeesDepositeTotal.text!)", forKey: "t_depo")
mutableDictionary.updateValue("300", forKey: "mini")
mutableDictionary.updateValue("\(RealIncomeTF.text ?? "0")", forKey: "real_earn")
mutableDictionary.updateValue("\(RealIncomeTF.text ?? "0")", forKey: "mb_balance")
mutableDictionary.updateValue("\(newBalanceLabel.text ?? "0")", forKey: "balance_for")
ary.append(mutableDictionary)


mutableArray = NSMutableArray(array: ary)


print(mutableArray)

我这样传递参数:

let parameters: Parameters = [
"insert": "0",
"Data": "\(mutableArray!)"
]

这是我打印可变数组时的控制台

(
{
"balance_for" = "-231.0";
"date_list" = "2018/04/20";
"e_id" = 566;
"mb_balance" = 33;
mini = 300;
"real_earn" = 33;
"t_depo" = 264;
"user_id" = 46;
}
)

当我打印参数时:

["insert": "0", "Data": "(\n        {\n        \"balance_for\" = \"-10.0\";\n        \"date_list\" = \"2018/04/20\";\n        \"e_id\" = 566;\n        \"mb_balance\" = 6;\n        mini = 300;\n        \"real_earn\" = 6;\n        \"t_depo\" = 16;\n        \"user_id\" = 46;\n    }\n)"]

最佳答案

试试这个

var dict = [String: String]()  
dict["user_id"] = "46"
dict["e_id"] ="566"
dict["date_list"] = "2018/04/20"
dict["t_depo"] = " 0.0"
dict["mini"] = "200"
dict["real_earn"] = "-5000.0"
dict["mb_balance"] = "-4000.0"
dict["balance_for"] = "4000"
var dictArray = [dict];
print(dictArray)

关于ios - 如何获取包含字典的数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49939202/

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