swift - Alamofire Swift 转换

Question

嗨，我想向 API 发出请求，但是发送时，控制台显示给我

invalidURL

 Alamofire.request("https://.../api/v1.8/set/order/?address=\(address)&email=\(email)&information=\(information)&name=\(name)&order=\(parameters)&password=\(password)&paymentType=\(paymentType)&phone=\(phone)&token=\(token)&userID=\(userID)&wihtRegistration=\(wihtRegistration)").validate(statusCode: 200..<300)
        .responseJSON { response in
        switch response.result
        {
        case .failure(let error):
            print(error)

        case .success(let value):
             print(value)

        print("Request: \(response.request)")

    }
}

如何在 Alamofire 中进行转换？

Answer 1

我创建了这个自定义方法。通过传递所需参数来调用它:-

没有 JSON 编码

func requestWithoutJSONEncoding(_ method: HTTPMethod
    , _ URLString: String
    , parameters: [String : AnyObject]? = [:]
    , headers: [String : String]? = [:]
    , completion:@escaping (Any?) -> Void
    , failure: @escaping (Error?) -> Void) {

    Alamofire.request(URLString, method: method, parameters: parameters, headers: headers)
        .responseJSON { response in

            switch response.result {
            case .success:
                completion(response.result.value!)
            case .failure(let error):
                failure(error)
            }
    }
}

使用 JSON 编码

func request(_ method: HTTPMethod
    , _ URLString: String
    , parameters: [String : AnyObject]? = [:]
    , headers: [String : String]? = [:]
    , completion:@escaping (Any?) -> Void
    , failure: @escaping (Error?) -> Void) {

    Alamofire.request(URLString, method: method, parameters: parameters, encoding: JSONEncoding.default, headers: headers)
        .responseJSON { response in

            switch response.result {
            case .success:
                completion(response.result.value!)
            case .failure(let error):
                failure(error)
            }
    }
}