gpt4 book ai didi

javascript - 过滤对象键上的数组不为空

转载 作者:行者123 更新时间:2023-11-30 11:30:24 25 4
gpt4 key购买 nike

我正在尝试通过值不为空的对象键来过滤对象数组

var collection = [
{
"season": "ETE 18",
"group": "GRBABY",
"market": "ALL",
"department": "ALL",
"skuType": "ALL",
"orderType": "ASE",
"packagingType": "CI"
},
{
"season": "ETE 18",
"group": "MEN",
"market": "ALL",
"department": "ALL",
"skuType": "ALL",
"orderType": "ASE",
"packagingType": "CI"
},
{
"season": "ETE 18",
"group": "GRBABY",
"market": "NONE",
"department": "ALL",
"skuType": "ALL",
"orderType": "ASE",
"packagingType": "CI"
},
]

var filterList = {season: "", group: "GRBABY", market: "ALL", department: "",
skuType: ""}

var result = _.filter(collection , proPack => {
if (filterList.group !== '') {
return proPack.group === filterList.group;
} else {
return proPack;
}
});

console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

这对我来说适用于一个过滤器,但我无法找到一种方法来过滤所有其他具有值的键。

结果应该是:

result = [
{
"season": "ETE 18",
"group": "GRBABY",
"market": "ALL",
"department": "ALL",
"skuType": "ALL",
"orderType": "ASE",
"packagingType": "CI"
} ]

最佳答案

您可以删除空属性:

var collection = [{
"season": "ETE 18",
"group": "GRBABY",
"market": "ALL",
"department": "ALL",
"skuType": "ALL",
"orderType": "ASE",
"packagingType": "CI"
},
{
"season": "ETE 18",
"group": "MEN",
"market": "ALL",
"department": "ALL",
"skuType": "ALL",
"orderType": "ASE",
"packagingType": "CI"
},
{
"season": "ETE 18",
"group": "GRBABY",
"market": "NONE",
"department": "ALL",
"skuType": "ALL",
"orderType": "ASE",
"packagingType": "CI"
}
]

var filterList = {season: "", group: "GRBABY", market: "ALL", department: "",
skuType: ""}

var filterList = _.omitBy(filterList, _.isEmpty) // { group: "GRBABY", market: "ALL" }

var result = _.filter(collection, filterList)

console.log(filterList, result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

关于javascript - 过滤对象键上的数组不为空,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46447846/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com