javascript - 高效访问Array.prototype.filter单项返回

Question

我经常使用 Array.prototype.filter，我只希望一个元素为真。

由于过滤器返回结果数组，我发现自己需要始终访问该元素，所以我做了类似

knownRefundLogics.filter((refundLogic) => this.hasTag(refundLogic.underscoredName))[0]

假设:

knownRefundLogics = [{
    "underscoredName": "express_full_refund",
    "camelized": "expressFullRefund"
}, {
    "underscoredName": "express_partial_refund",
    "camelized": "expressPartialRefund"
}, {
    "underscoredName": "express_no_refund",
    "camelized": "expressNoRefund"
}]

和hasTag() 一种方法，它在数组上为refundLogic 元素执行includes()。

是否有更合适的方法来做到这一点，例如使用展开运算符？

顺便说一下，我知道我可能会以仅返回 true 或 false 值的方式拆分我的方法，但我发现这个解决方案有点过度设计.

Answer 1

使用Array#find () 而不是 - 只要谓词返回 true，迭代就会停止，并立即返回匹配项(不是数组):

const knownRefundLogics = [{"underscoredName":"express_full_refund","camelized":"expressFullRefund"},{"underscoredName":"express_partial_refund","camelized":"expressPartialRefund"},{"underscoredName":"express_no_refund","camelized":"expressNoRefund"}];

const demoHasTag = (t) => t === 'express_partial_refund';

const result = knownRefundLogics.find((refundLogic) => demoHasTag(refundLogic.underscoredName));

console.log(result);