gpt4 book ai didi

javascript - D3.js 可折叠树 : Adding a label for each level

转载 作者:行者123 更新时间:2023-11-30 11:28:46 25 4
gpt4 key购买 nike

我正在开发一个项目,该项目需要为 D3.js 中可折叠树的每个级别添加一个标签(https://bl.ocks.org/mbostock/4339083)。我在添加相同内容时面临困难时期。我需要的标签已添加到随附的屏幕截图中。单击每个级别后,标签应立即为每个级别填充,并在树回滚时消失。谁能帮我解决这个问题。 enter image description here

最佳答案

修改更新方法以跟踪节点项的级别。维护来自用于绘制图表的节点项的所有深度值的唯一排序哈希。获得排序后的 depthHash 数组后,将文本绘制在图表顶部。以下是我修改过的 fiddle 供您引用。 http://jsfiddle.net/deepakpster/vomxqxov/3/

var margin = {top: 20, right: 120, bottom: 20, left: 120},
width = 960 - margin.right - margin.left,
height = 800 - margin.top - margin.bottom;

var i = 0,
duration = 750,
root;

var tree = d3.layout.tree()
.size([height, width]);

var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });

var svg = d3.select("body").append("svg")
.attr("width", width + margin.right + margin.left)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");

flare = "http://rawgit.com/mbostock/1093025/raw/a05a94858375bd0ae023f6950a2b13fac5127637/flare.json"
d3.json(flare, function(error, flare) {
root = flare;
root.x0 = height / 2;
root.y0 = 0;

function collapse(d) {
if (d.children) {
d._children = d.children;
d._children.forEach(collapse);
d.children = null;
}
}

root.children.forEach(collapse);
update(root);
});

d3.select(self.frameElement).style("height", "800px");

function update(source) {

// Compute the new tree layout.
var nodes = tree.nodes(root).reverse(),
links = tree.links(nodes);

// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * 180; });
// Showing the labels for the level of depths.
// Using underscore.js to do the pluck, uniq.
var depthHash = _.uniq(_.pluck(nodes, "depth")).sort();
svg.selectAll("g.levels-svg").remove();
var levelSVG = svg.append("g").attr("class", "levels-svg");
var levels = levelSVG.selectAll("g.level");
levels.data(depthHash)
.enter().append("g")
.attr("class", "level")
.attr("transform", function(d) { return "translate(" + d*180 + "," + 10 + ")"; })
.append("text")
.text(function(d){
return "level-" + d;
});

// Update the nodes…
var node = svg.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });

// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
.on("click", click);

/*
nodeEnter.append("circle")
.attr("r", 1e-6)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
*/
var ww = 30, hh = 20
nodeEnter.append("rect")
.attr("height", 1e-6)
.attr("width", 1e-6)
.attr("x", -ww/2)
.attr("y", -hh/2)
.attr("rx", 3)
.attr("ry", 3)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

nodeEnter.append("text")
.attr("x", function(d) { return d.children || d._children ? -10 : 10; })
.attr("dy", ".35em")
.attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
.text(function(d) { return d.name; })
.style("fill-opacity", 1e-6);

// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });

nodeUpdate.select("rect")
.attr("width", ww)
.attr("height", hh)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

nodeUpdate.select("circle")
.attr("r", 4.5)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

nodeUpdate.select("text")
.attr("dx", -10)
.style("fill-opacity", 1);

// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.remove();

nodeExit.select("circle")
.attr("r", 1e-6);

nodeExit.select("text")
.style("fill-opacity", 1e-6);

// Update the links…
var link = svg.selectAll("path.link")
.data(links, function(d) { return d.target.id; });

// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
});

// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);

// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();

// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
}

// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(d);
}

关于javascript - D3.js 可折叠树 : Adding a label for each level,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47059043/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com