Java 文件输出检查

Question

我刚刚写了很多代码，我正在尝试用这段代码写一个输出文件-

File outfile = new File ("output.txt");
PrintWriter outFile = new PrintWriter(outfile);
outFile.printf("%-20s%5s%5s%5s%5s", f,median,avg,min,max);
outFile.println("");
outFile.printf("%-20s%5s%5s%5s%5s", f,median,avg,min,max);
outFile.println("");
outFile.printf("%-27s%5d%5d%5d%5d", firstplayer,P1median,P1avg,PScore.get(0),PScore.get(PScore.size()-1));
outFile.println("");
outFile.printf("%-27s%5d%5d%5d%5d", secondplayer,P2median,P2avg,Player2.get(0),Player2.get(Player2.size()-1));
outFile.println("");
outFile.printf("%-27s%5d%5d%5d%5d",fourthplayer,P4median,P4avg,Player4.get(0),Player4.get(Player4.size()-1));
outFile.close();

现在我没有抛出任何错误或异常，我相信我已经成功地编写了一个输出文件，但是我不知道它位于何处以及如何检查它的内容。如果这是一个糟糕的问题，我深表歉意，但我一直在努力寻找其他地方的答案，因此非常感谢任何帮助找到输出文件或纠正我的错误。

Answer 1

如果您仍然不确定它的位置，这将打印出完整的文件路径:

System.out.println(outfile.getAbsolutePath());

如果你想打印出文件的内容以便在你的程序中检查它:

//ensure content in file is updated
outfile.flush();

BufferedReader br = null;
try {
    br = new BufferedReader(new FileReader(outfile));
    String line;
    while ((line = br.readLine()) != null) {
         System.out.println(line);
    }
}
catch (IOException e) {
    e.printStackTrace();
}
finally {
    try {
        br.close();
    }
    catch (IOException e) {
        e.printStackTrace();
    }
}

确保同时关闭该文件。