java - 如何为 XmlRootElement 添加后缀

Question

我已经试过了:

包信息.java

@XmlSchema(xmlns= 
{
    @XmlNs(prefix="Person", namespaceURI="sample.url.something"),
    @XmlNs(prefix="xsi", namespaceURI="http://www.w3.org/2001/XMLSchema-instance")
})

Java

@XmlRootElement(name = "Person:sampleData")
public class Person {

    private static String path = "files/test.xml";

    @XmlElement()
    public String Name;

    @XmlElement()
    public int Age;

    public Person(){}

    public Person(String name, int age){
        this.Name = name;
        this.Age = age;
    }

    public static String PersonToXMLString(Person person) throws JAXBException
    {
        JAXBContext jc = JAXBContext.newInstance(Person.class);
        StringWriter sw = new StringWriter();
        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.setProperty(Marshaller.JAXB_SCHEMA_LOCATION, "somelocation.xsd");
        marshaller.marshal(person, sw);
        return sw.toString();
    }

    public static Person XMLStringToPerson() throws JAXBException
    {
        JAXBContext jaxbContext = JAXBContext.newInstance(Person.class);
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
        Person Person = (Person) unmarshaller.unmarshal(new File(path));
        return Person;
    }

    public static void WriteXMLStringFile(String xml) throws IOException
    {
        File file = new File(path);
        try (FileOutputStream fop = new FileOutputStream(file)) {
            if (!file.exists()) {
                file.createNewFile();
            }
            byte[] contentInBytes = xml.getBytes();
            fop.write(contentInBytes);
            fop.flush();
            fop.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    public static String ReadXmlStringFromFile() throws IOException 
    {
        BufferedReader br = new BufferedReader(new FileReader(new File(path)));
        String line;
        StringBuilder sb = new StringBuilder();
        while ((line = br.readLine()) != null) {
            sb.append(line.trim());
        }
        return sb.toString();
    }

    public static void main(String[] args) throws JAXBException, IOException
    {       
        Person user = new Person("User",23);

        String xml = user.PersonToXMLString(user);
        System.out.println(xml);
        user.WriteXMLStringFile(xml);

        xml = user.ReadXmlStringFromFile();
        //used to unmarshall xml to Person object
        Person person = user.XMLStringToPerson();
        System.out.println(person.Name);
    }
}

XML

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Person:sampleData xmlns:Person="sample.url.something" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <Name>User</Name>
    <Age>23</Age>
</Person:sampleData>

如果我做这样的事情，我会在解码时遇到异常:

线程“main”中的异常 javax.xml.bind.UnmarshalException:意外元素(uri:“sample.url.something”，local:“sampleData”)。预期的元素是 <{}Person:sampleData>`

仅供引用:我无法修改 XML。

感谢收到的任何帮助!

Answer 1

您可以执行以下操作:

package-info.java

您的 @XmlSchema 注释在您的 package-info 类中应该类似于以下内容。由于 elementFormDefault 被指定为 UNQUALIFIED，命名空间将仅应用于全局元素(在 JAXB 中对应于 @XmlRootElement 的元素)。请注意，在编码 XML 时，不需要 JAXB impl 来使用 @XmlSchema 中包含的前缀。

@XmlSchema(
    elementFormDefault=XmlNsForm.UNQUALIFIED,
    namespace="sample.url.something",
    xmlns={
        @XmlNs(prefix="Person", namespaceURI="sample.url.something")
    }
)
package com.example;

import javax.xml.bind.annotation.*;

人

@XmlRootElement 注释不应包含前缀。

 package com.example;

 import javax.xml.bind.annotation.*;

 @XmlRootElement(name="sampleData")
 public class Person {

了解更多信息

您可以在我的博客上阅读有关在 JAXB 中控制命名空间前缀的更多信息:

• http://blog.bdoughan.com/2011/11/jaxb-and-namespace-prefixes.html