javascript - 在 Javascript 对象中查找和替换键

Question

我正在访问返回的 JSON，如下所示:

[
{
    "itemType": "SelectionTitle",
    "name": "1105F.MID",
    "active": true,
    "isFactoryDefault": false,
    "factoryCode": "",
    "seasons": [],
    "denominations": [],
    "groups": [],
    "length": 0,
    "_id": "5ada2217c114ca048e1db9b0",
    "created_by": "5ab57289d8d00507b29a3fdd",
    "selectionFile": {
        "itemType": "SelectionFile",
        "name": "1105F.MID",
        "active": true,
        "isFactoryDefault": false,
        "selectionType": "Music",
        "sfzFile": "",
        "destination": "/data/uploads",
        "encoding": "7bit",
        "fieldname": "file",
        "filename": "782f49a7cd72b865b4e2d286816792e7",

...
        "found": true,
        "flError": false,
        "error_strings": [],
        "_id": "5ada2217c114ca048e1db9af",
        "created_by": "5ab57289d8d00507b29a3fdd",
        "slug": "1105fmid",
        "__v": 0,
        "createdAt": "2018-04-20T17:23:35.216Z",
        "updatedAt": "2018-04-20T17:23:35.788Z",
        "selectionTitles": null,
        "id": "5ada2217c114ca048e1db9af"
    },
    "slug": "1105fmid",
    "createdAt": "2018-04-20T17:23:35.285Z",
    "updatedAt": "2018-04-20T17:23:35.285Z",
    "__v": 0,
    "id": "5ada2217c114ca048e1db9b0"
}, ...

我正在使用的 react-select 节点模块采用键“标签”来生成填充的下拉列表。

JSON 来自网络，因此我无法控制 JSON 的设置方式。如何解析 JSON 以找到“name”的所有实例并将该键替换为“label”？

例如 "name": 1105F.MID"应该改为 "label": "1105.MID"

将整个东西转换为字符串并使用 javascript 方法查找/替换会不会效率低下？

Answer 1

假设您的 JSON 数组存储在变量 data 中:

data.forEach(item => item.label = item.name)

这足以将 name 属性复制为数组中每个项目的 label 属性。