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ios - Bolt-Swift : error handling

转载 作者:行者123 更新时间:2023-11-30 11:12:26 24 4
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我想使用 BoltsSwift ( https://github.com/BoltsFramework/Bolts-Swift )。

但我无法正确处理错误。

在下面的示例中,为什么运行的是“taskHello2.continueOnSuccessWith”而不是“taskHello2.continueOnErrorWith”?

谢谢

func testTask() {
let taskHello1 = echo("hello1")
let taskHello2 = taskHello1.continueOnSuccessWith(continuation: { (task) -> Task<String> in
let taskResult = self.echo("error")
return taskResult
})
_ = taskHello2.continueOnErrorWith(continuation: { (task) -> Task<String> in
let taskResult = self.echo("Error received")
return taskResult
})
_ = taskHello2.continueOnSuccessWith(continuation: { (task) -> Task<String> in
let taskResult = self.echo("Success received")
return taskResult
})
}

func echo(_ text: String) -> Task<String> {
let taskCompletionSource = TaskCompletionSource<String>()
print("=> \(text)")
switch (text) {
case "error":
let error = NSError(domain: "domain", code: -1, userInfo: ["userInfo": "userInfo"])
taskCompletionSource.set(error: error)
case "cancel":
taskCompletionSource.cancel()
default:
taskCompletionSource.set(result: text)
}
return taskCompletionSource.task
}

输出:

=> hello1
=> error
=> Success received

最佳答案

函数continueOnErrorWith(continuation:)仅在出现错误时运行——任务发生故障。

在您的 testTask() 函数中,taskHello1 被执行(或成功),因此 'hello1' 被打印到控制台。

在代码中:

let taskHello2 = taskHello1.continueOnSuccessWith(continuation: { (task) -> Task<String> in
let taskResult = self.echo("error")
return taskResult
})

由于 taskHello1 已经成功,因此闭包内的代码被执行并且'错误'打印。

内部代码:

_ = taskHello2.continueOnErrorWith(continuation: { (task) -> Task<String> in
let taskResult = self.echo("Error received")
return taskResult
})

由于taskHello2未遇到错误,闭包内的代码未执行并且“收到错误” 未打印到控制台。

代码中类似:

_ = taskHello2.continueOnSuccessWith(continuation: { (task) -> Task<String> in
let taskResult = self.echo("Success received")
return taskResult
})

由于taskHello2成功,闭包内的代码被执行并且'成功收到'打印。

关于ios - Bolt-Swift : error handling,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52046135/

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