javascript - 使用 Javascript 从 Json 中的子元素创建新键

Question

我想使用 ES6/ES5 从 json 中的子值创建新键。我尝试使用箭头函数，但无法得到结果。首先你可以在下面看到我的 json 部分，

[  
   {  
      matchId:307,
      matchStatusId:5,
      matchHomeScore:0,
      matchAwayScore:0,
      matchTime:0,
      homeClubId:608,
      homeClub:{  
         clubId:608,
         clubName:"Annaba"
      },
      awayClubId:609,
      awayClub:{  
         clubId:609,
         clubName:"Bazer Sakhra"
      },
      leagues:[  
         {  
            leagueId:65,
            parentLeagueId:null,
            leagueName:"ALGERIA"
         },
         {  
            leagueId:66,
            parentLeagueId:65,
            leagueName:"Algeria Cup"
         }
      ]
   },
]

我想创建新的父 key 。它将从子项的值中获取值并将其合并。子项编号可变。不是每次 2 项。leaguesGeneral:"ALGERIA - Algolia 杯"

   leaguesGeneral:"ALGERIA - Algeria Cup"   
   leagues: [  
      {  
         leagueId:65,
         parentLeagueId:null,
         leagueName:"ALGERIA"
      },
      {  
         leagueId:66,
         parentLeagueId:65,
         leagueName:"Algeria Cup"
      }
   ]

我找到了这个方法。但它结合了父级的所有内容。

data = data.map(function (x) {
    var keys = Object.keys(x);
    x.newKeyValue = keys.map(key => x[key]).join('-');
    return x;
});

Answer 1

leaguesGeneral 键可以添加到数组中的每个对象，使用

o.leagues.map(({ leagueName }) => leagueName).join(' - ')

const data = [  
   {  
      matchId:307,
      matchStatusId:5,
      matchHomeScore:0,
      matchAwayScore:0,
      matchTime:0,
      homeClubId:608,
      homeClub:{  
         clubId:608,
         clubName:"Annaba"
      },
      awayClubId:609,
      awayClub:{  
         clubId:609,
         clubName:"Bazer Sakhra"
      },
      leagues:[  
         {  
            leagueId:65,
            parentLeagueId:null,
            leagueName:"ALGERIA"
         },
         {  
            leagueId:66,
            parentLeagueId:65,
            leagueName:"Algeria Cup"
         }
      ]
   },
];

const result = data.map(o => {
  if (o.leagues) {
    o.leaguesGeneral = o.leagues.map(({ leagueName }) => leagueName).join(' - ');
  }
  return o;
})

console.log(result)