javascript - 如何将对象数组的数据转换为更有意义的嵌套对象和数组结构？

Question

除非结构良好，否则数据毫无用处。我想通过 vanilla JavaScript 将对象数组转换为更有意义的结构化对象 - 以减少世界上的熵:)

公司的值形成嵌套的命名数组，车辆的值形成嵌套的命名对象。最困难的任务是动态设置 if 语句。我卡在了代码的最后，希望 JS 专家能帮助我。

//源数据格式

var inputs = [
    {"vehicle":"car", "company":"Toyota", "model":"Corolla"},
    {"vehicle":"car", "company":"Toyota", "model":"Rav4"},
    {"vehicle":"car", "company":"Toyota", "model":"Camry"},
    {"vehicle":"car", "company":"Chevrolet", "model":"Malibu"},
    {"vehicle":"car", "company":"Chevrolet", "model":"Camaro"},
    {"vehicle":"rocket", "company":"Tesla", "model":"SpaceX"}
];

//目标数据格式

const data = {
    car:{
        Toyota:[
            {"vehicle"="car","company"="Toyota", "model"="Corolla"},
            {"vehicle"="car","company"="Toyota", "model"="Rav4"},
            {"vehicle"="car","company"="Toyota", "model"="Camry"}
        ],
        Chevrolet:[
            {"vehicle"="car","company"="Chevrolet", "model"="Malibu"},
            {"vehicle"="car","company"="Chevrolet", "model"="Camaro"}
        ]
    },
    rocket:{
        Tesla:[
            {"vehicle"="rocket","company"="Tesla", "model"="SpaceX"}
        ]
    }
};

//未完成的解决方案

// Get all vehicle names.
var vehicles = [];
for (var [key, obj] of inputs.entries()) {
    vehicles.push(obj.vehicle);
}

// Single out only unique vehicle names.
var uniqueVehicles = [...new Set(vehicles)];

// Get all company names.
var arr = [];
for (var [key, obj] of inputs.entries()) {
    arr.push(obj.company);
}

// Single out only unique company names.
var uniqueCompanies = [...new Set(arr)];

// Group objects into arrays by company names.
var dataProperties = {};
for (var comp of uniqueCompanies) {
    dataProperties[comp] = inputs.filter(obj => obj.company === comp);  
}

// Group objects into arrays by vehicle names.
var data = {};
for (var vehi of uniqueVehicles) {
    data[vehi] = inputs.filter(o => o.vehicle === vehi);
}
// data;
// dataProperties;

Answer 1

这是我的做法:

function transform(data) {
  let result = {};
  data.forEach(element => {
    // Reuse the existing vehicle object, or create an empty one if it doesn't exist
    result[element.vehicle] = result[element.vehicle] || {};
    // Reuse the existing company array, or create an empty one if it doesn't exist
    result[element.vehicle][element.company] = result[element.vehicle][element.company] || [];
    result[element.vehicle][element.company].push(element);
  })
  return result;
}

const inputs = [
  {"vehicle":"car", "company":"Toyota", "model":"Corolla"},
  {"vehicle":"car", "company":"Toyota", "model":"Rav4"},
  {"vehicle":"car", "company":"Toyota", "model":"Camry"},
  {"vehicle":"car", "company":"Chevrolet", "model":"Malibu"},
  {"vehicle":"car", "company":"Chevrolet", "model":"Camaro"},
  {"vehicle":"rocket", "company":"Tesla", "model":"SpaceX"}
];

const output = transform(inputs);
console.log(output);