ios - 根据对象属性过滤任何对象的数组

Question

我收到了这种格式的回复

[
    "1234": {
        "startDate": "1536278400",
        "endDate": "1536796800",
        "playerRank": 1,
        "performance": 100,
        "isProfit": false,
        "members": 1
    },
    "adityaKumar": {
        "startDate": "1536364800",
        "endDate": "1540080000",
        "playerRank": 1,
        "performance": 100,
        "isProfit": false,
        "members": 6
    },
    "madhu60": {
        "startDate": "1539388800",
        "endDate": "1539475200",
        "playerRank": 1,
        "performance": 100,
        "isProfit": false,
        "members": 2
    }
]

此响应的类型为[string:Any]。我必须使用 playerRank 属性对数据进行排序。我希望输出的类型为 [string:Any]。

这在 Swift 中怎么可能？

Answer 1

字典未排序

来自swift documentation

A dictionary stores associations between keys of the same type and values of the same type in an collection with no defined ordering.

但是，您可以在字典上使用 .sorted 方法，这将为您提供一个字典数组(数组是可排序的)。

let sorted = dictionary.sorted(by: { ($0.value["playerRank"]) < ($1.value["playerRank"]) })

从你原来的例子中sorted可能看起来像这样

[
    (
      "key": "madhu60",
      "value": {
         "startDate": "1539388800",
         "endDate": "1539475200",
         "playerRank": 1,
         "performance": 100,
         "isProfit": false,
         "members": 2
      }
   )
   ....
]