java - 输出该数字以及重复序列的单个字符

Question

伙计们!我一直在 Java 上练习不同的任务，而这个任务花了我一段时间才弄明白。用户只需输入 String 字母，例如，如果用户输入类似 wwwzddfffff 的 smth，则输出应为 3w1z2d5f 或者，另一个示例, kklllk 并且输出应该是 3k3l。 runLength() 方法获取每个重复字符的出现并输出该数字以及重复序列的单个字符。
我得到的是:

Enter any String: 
wwwwzzzz
7z




    import java.util.Scanner;

public class RunLength {

    public static void main(String[] args)
    {
        Scanner kbd = new Scanner(System.in);
        System.out.println("Enter any String: ");
        String word = kbd.nextLine();
        String result = runLength(word);
        System.out.println(result);
    }

    public static String runLength(String word)
    {
        char[] chars = word.toCharArray();
        char firstChar = chars[0];
        char temp = 0;
        int count = 0;
        String result = "";

        for(int i = 1; i < chars.length; i++)
        {

            if(firstChar == chars[i])
            {
                temp = firstChar;
                count++;
                result = count+""+temp;
            }

            else if(firstChar != chars[i])
            {
                temp = chars[i];
                count++;
                result = count+""+temp;
            }
        }

        return result;
    }

}

Answer 1

class test
{


public static void main(String args[])
    {
        System.out.println(runlength("aaabbc"));
    }
static String runlength(String s)
{
    String current="";
    int count = 1;
    char[] c = s.toCharArray();
    for(int i = 1; i < c.length; i++)
    {
        if (c[i]==c[i-1])
            count++;

        else 
        {
            current = current + count + Character.toString(c[i-1]);
            count = 1;
        }
    }
    return current + count + Character.toString(c[c.length-1]);
}
}