java - 连接四个垂直赢家

Question

由于某些原因，当内部四个循环运行完毕时，此方法不会将 1 加到外部 for 循环中的 col。我只能在 col 设置的列中获得垂直连接四肢。例如，如果 col 等于 2，计算机将只能识别第 2 列中的垂直连接四。有什么问题吗？

public Player colWinner(){
        for(int col = 0; col < grid[0].length; col++){
            for(int row = 0; row < grid.length/2; row++){
                Player currP = getCell(row,col);
                if((currP == getCell(row + 1, col)) && (currP == getCell(row + 2, col)) && (currP == getCell(row + 3, col))){ 
                    return currP;
                }
                else{
                    continue;
                }
            }
            for(int row = grid.length/2; row < grid.length; row++){
                Player currP = getCell(row,col);
                if((currP == getCell(row - 1, col)) && (currP == getCell(row - 2, col)) && (currP == getCell(row - 3, col))){ 
                    return currP;
                }
                else{
                    continue;
                }
            }
        }
        return null;
    }

Answer 1

我认为您的代码允许 4 个垂直空序列。需要为每个 if 语句添加 currP != null。

public Player colWinner(){
    for(int col = 0; col < grid[0].length; col++){
        for(int row = 0; row < grid.length/2; row++){
            Player currP = getCell(row,col);
            if(currP != null && currP == getCell(row + 1, col) && currP == getCell(row + 2, col) && currP == getCell(row + 3, col)){ 
                return currP;
            }
        }
        for(int row = grid.length/2; row < grid.length; row++){
            Player currP = getCell(row,col);
            if(currP != null && currP == getCell(row - 1, col) && currP == getCell(row - 2, col) && currP == getCell(row - 3, col)){ 
                return currP;
            }
        }
    }
    return null;
}