gpt4 book ai didi

java - 如何让 Apache Tika 在 .java 和 .xml(等)文件中查找文本

转载 作者:行者123 更新时间:2023-11-30 10:59:31 25 4
gpt4 key购买 nike

好的。我想出了如何使用 Apache Tika 搜索它可以处理的一些文件类型,而无需我提供比 tika-example 中存在的代码更多的代码:

public class MyFirstTika {

public static boolean contains(File file, String s) throws MalformedURLException,
IOException, MimeTypeException, SAXException, TikaException{

ContentHandler handler = new BodyContentHandler();

MimeTypes mimeRegistry = TikaConfig.getDefaultConfig().getMimeRepository();

Detector mimeDetector = (Detector) mimeRegistry;

LanguageIdentifier lang = new LanguageIdentifier(new LanguageProfile(FileUtils.readFileToString(file)));

Parser parser = TikaConfig.getDefaultConfig().getParser(MediaType.parse(mimeRegistry.getMimeType(file).getName()));

Metadata parsedMet = new Metadata();

parser.parse(file.toURI().toURL().openStream(), handler,parsedMet, new ParseContext());

return handler.toString().toLowerCase().contains(s.toLowerCase());
}

public static void main(String[] args) throws Exception
{
String searchString = "champion";
String filename = "schedule.pdf"; //test.docx";//"meds.xlsx";//Test2.Doc";
File file = new File(filename);

System.out.println(file + " contains " + searchString + ": "
+ contains(file, searchString));
}
}

以上可以判断以下文件类型是否包含单词或短语:.doc.docx.xlsx.pdf。TXT.html

它不适用于 .java 文件或 .xml 文件。

(a) 我需要做什么我想查看扩展名为 .java.xml 的文本文件是否包含单词或短语?

(b) 这些不是我经常创建或编辑的唯一类型的文件。有没有办法让 Apache Tika 在不指定扩展名的情况下检测文件是否为文本文件?

编辑 背景:我为 Windows 编写了一个比搜索命令更好用的搜索程序。现在,我正在尝试在模式匹配文件中添加对特定文本的搜索。

编辑

这是当我在 Copy.java 中搜索 void 时程序的输出(经过修改以提供以下信息):

Examining: [copy.java]
The MIME type (based on filename) is: [text/x-java-source]
The MIME type (based on MAGIC) is: [application/octet-stream
The MIME type (based on the Detector interface) is: [text/plain]
The language of this content is: [et]
Parsed Metadata:

Parsed Text:

copy.java contains void: false

那么为什么它没有找到 void? (答案:因为它没有找到任何Parsed MetadataParsed Text,但为什么没有找到那些?它应该显示整个文件。

我将 copy.java 复制到 copy.txt。程序 DID 发现 void。当我将 build.xml 复制到 build.txt 时发生了同样的事情。

也许这个添加的信息有助于回答这个问题:“我如何处理 .java.xml 以及其他文本文件,例如 .c 等等?”

请注意搜索 copy.TXT 的输出:

run:
Examining: [copy.TXT]
The MIME type (based on filename) is: [text/plain]
The MIME type (based on MAGIC) is: [application/octet-stream
The MIME type (based on the Detector interface) is: [text/plain]
The language of this content is: [et]

解析的元数据:

Content-Encoding=UTF-8 Content-Type=text/plain; charset=UTF-8 

解析的文本:

  public static void main(String[] args) throws IOException {
EventQueue.invokeLater(new Runnable()
{ @Override
public void run() {
insUserIO = new UserIO();
}
}
);
}

copy.TXT contains void: true
BUILD SUCCESSFUL (total time: 1 second)

整个修改后的程序

    package org.apache.tika.example;

import java.io.File;
import java.io.IOException;
import java.net.MalformedURLException;

import org.apache.commons.io.FileUtils;
import org.apache.tika.config.TikaConfig;
import org.apache.tika.detect.Detector;
import org.apache.tika.exception.TikaException;
import org.apache.tika.language.LanguageIdentifier;
import org.apache.tika.language.LanguageProfile;
import org.apache.tika.metadata.Metadata;
import org.apache.tika.mime.MediaType;
import org.apache.tika.mime.MimeTypeException;
import org.apache.tika.mime.MimeTypes;
import org.apache.tika.parser.ParseContext;
import org.apache.tika.parser.Parser;
import org.apache.tika.sax.BodyContentHandler;
import org.xml.sax.ContentHandler;
import org.xml.sax.SAXException;

public class MyFirstTika {

static boolean debugging = true;

public static boolean contains(File file, String s) throws MalformedURLException, IOException, MimeTypeException, SAXException, TikaException{

ContentHandler handler = new BodyContentHandler();

MimeTypes mimeRegistry = TikaConfig.getDefaultConfig()
.getMimeRepository();

if(debugging) System.out.println("Examining: [" + file + "]");

if(debugging) System.out.println("The MIME type (based on filename) is: ["
+ mimeRegistry.getMimeType(file.toString()) + "]");

if(debugging) System.out.println("The MIME type (based on MAGIC) is: ["
+ mimeRegistry.getMimeType(file + "]"));

Detector mimeDetector = (Detector) mimeRegistry;
if(debugging) System.out
.println("The MIME type (based on the Detector interface) is: ["
+ mimeDetector.detect(file.toURI().toURL()
.openStream(), new Metadata()) + "]");

LanguageIdentifier lang = new LanguageIdentifier(new LanguageProfile(
FileUtils.readFileToString(file)));

if(debugging) System.out.println("The language of this content is: ["
+ lang.getLanguage() + "]");

Parser parser = TikaConfig.getDefaultConfig().getParser(
MediaType.parse(mimeRegistry.getMimeType(file).getName()));

Metadata parsedMet = new Metadata();
parser.parse(file.toURI().toURL().openStream(), handler,
parsedMet, new ParseContext());

if(debugging) System.out.println("Parsed Metadata: ");
if(debugging) System.out.println(parsedMet);
if(debugging) System.out.println("Parsed Text: ");
if(debugging) System.out.println(handler.toString());
return handler.toString().toLowerCase().contains(s.toLowerCase());
}

public static void main(String[] args) throws Exception
{
File file = new File(filename);

System.out.println(file + " contains " + searchString + ": "
+ contains(file, searchString));
}

static String searchString = "void";
static String filename = "copy.TXT";
}

最佳答案

非常感谢@Gagravarr 引导我使用AutoDetectParser!

下面的小程序在所有类型的“文本”(人类可读)(和其他——例如,.doc*)文件中找到了文本,包括 private.propertiesParsingExample.java(本身!)、test.doctest.pdf(由 Word 制作)、gradlew。 bat 等等等等

package org.apache.tika.example;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.MalformedURLException;
import org.apache.tika.exception.TikaException;
import org.apache.tika.metadata.Metadata;
import org.apache.tika.mime.MimeTypeException;
import org.apache.tika.parser.AutoDetectParser;
import org.apache.tika.sax.BodyContentHandler;
import org.xml.sax.SAXException;

public class ParsingExample {

public static boolean contains(File file, String s) throws MalformedURLException,
IOException, MimeTypeException, SAXException, TikaException
{
InputStream stream = new FileInputStream(file);
AutoDetectParser parser = new AutoDetectParser();
BodyContentHandler handler = new BodyContentHandler(-1);
Metadata metadata = new Metadata();
try{
parser.parse(stream, handler, metadata);
return handler.toString().toLowerCase().contains(s.toLowerCase());
}
catch (IOException | SAXException | TikaException e){
System.out.println(file + ": " + e + "\n");
return false;
}
}
public static void main(String[] args)
{
try {
System.out.println("File " + filename + " contains <" + searchString + "> : "
+ contains(new File(filename), searchString));
} catch (IOException | SAXException | TikaException ex){
System.out.println("Error: " + ex);
}
}

static String parseExample = ":(";
static String searchString = "slom";
static String filename = "C:\\Users\\Dov\\x.pdf";
}
/**
* Example of how to use Tika to parse a file when you do not know its file type
* ahead of time.
*
* AutoDetectParser attempts to discover the file's type automatically, then call
* the exact Parser built for that file type.
*
* The stream to be parsed by the Parser. In this case, we get a file from the
* resources folder of this project.
*
* Handlers are used to get the exact information you want out of the host of
* information gathered by Parsers. The body content handler, intuitively, extracts
* everything that would go between HTML body tags.
*
* The Metadata object will be filled by the Parser with Metadata discovered about
* the file being parsed.
*
* Note: This example will extract content from the outer document and all
* embedded documents. However, if you choose to use a {@link ParseContext},
* make sure to set a {@link Parser} or else embedded content will not be
* parsed.
*
* @return The content of a file.
* I let Netbeans add next 3 lines:
* @throws java.io.IOException
* @throws org.xml.sax.SAXException
* @throws org.apache.tika.exception.TikaException
*/

关于java - 如何让 Apache Tika 在 .java 和 .xml(等)文件中查找文本,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31889104/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com