Javascript Switch 语句多例返回值

Question

我有一个 json 对象，我从中获取数据，其中包含值(奶牛:'是'，鸡:'NULL')和(奶牛:'是'，鸡:'是')等。我想仅显示具有"is"的值，然后显示它们的值。目前我只能返回包含"is"的第一个案例，例如它只返回“牛”，但目标是返回“牛，鸡”，如果两者都具有"is"值。我在这里做错了什么？或者如果有更好的方法，谢谢您的帮助。

switch ("Yes") {
    case popup.properties.Beef:   return "<span>Cows</span>";
    case popup.properties.Pork: return "<span>Pigs</span>";
    case popup.properties.Sheep:  return "<span>Sheep</span>";
    case popup.properties.Goat: return "<span>Goats</span>";
    case popup.properties.Lamb:  return "<span>Lambs</span>";
    case popup.properties.Rabbit: return "<span>Rabbit</span>";
    case popup.properties.OtherMeat:  return "<span>Other</span>";
    case popup.properties.Chicken: return "<span>Chicken</span>";
    case popup.properties.Turkey:  return "<span>Turkey</span>";
    case popup.properties.Duck: return "<span>Duck</span>";
    case popup.properties.Goose:  return "<span>Geese</span>";
    case popup.properties.Pheasant: return "<span>Pheasants</span>";
    case popup.properties.Quail:  return "<span>Quail</span>";
    case popup.properties.OtherPoultry:  return "<span>Other Poultry</span>";
    default:      return "";
}

Answer 1

您可以获取具有所需值的对象并获取字符串数组。

var values = { Beef: "Cows", Pork: "Pigs", Sheep: "Sheep", Goat: "Goats", Lamb: "Lambs", Rabbit: "Rabbit", OtherMeat: "Other", Chicken: "Chicken", Turkey: "Turkey", Duck: "Duck", Goose: "Geese", Pheasant: "Pheasants", Quail: "Quail", OtherPoultry: "Other Poultry" };
    result = Object
        .keys(popup.properties)
        .filter(k => popup.properties[k] === 'Yes')
        .map(k => values[k]);