Java 从 dictionary.txt 文件中获取 100 个随机单词

Question

我有一个文本文件 rext.txt，我试图从文本的每一行中获取前 100 个随机单词文件并将它们放入字符串数组中，但它不起作用。我想出了如何将文件与文本分开并将它们放入数组中，但我不知道在哪里包含 100 来对它们进行排序。谢谢!!!

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Random;
import java.util.Scanner;

public class New2 
    {
     public static void main(String[] args) throws FileNotFoundException 
        {
         Scanner sc = new Scanner(new File("dictionary.txt"));
         while (sc.hasNext())   
             {
             String word = sc.next();
             sc.nextLine();   
             String[] wordArray = word.split(" "); 
             //System.out.println(Arrays.toString(wordArray));
             int idx = new Random().nextInt(wordArray.length);
             String random = (wordArray[idx]);
             System.out.println(random);


        }
}
}

Answer 1

首先，从文件中提取 100 个单词。然后随机化数组。

String[] words = new String[100];
int pos = 0;
Scanner sc = new Scanner(new File("dictionary.txt"));
while (sc.hasNextLine() && pos < words.length) {
    String line = sc.nextLine();
    String[] wordArray = line.split("\\s+"); // <-- one or more consecutive 
                         //  white space characters.
    for (String word : wordArray) {
        words[pos] = word;
        pos++;
        if (pos >= words.length) {
            break;
        }
    }
}

然后你可以随机播放并显示words like

Collections.shuffle(Arrays.asList(words));
System.out.println(Arrays.toString(words));